URL.getFile()中的错误 [英] Error in URL.getFile()

问题描述

我正在尝试从URL打开文件.

I am trying to open a file from URL.

URL的对象是使用ClassLoader的getResource()方法创建的. 从getResource()方法返回的输出URL是=

Object of URL is created with getResource() method of ClassLoader. Output URL returned from getResource() method is =

file:/C:/users/

使用URL.getFile()方法返回String为"/C:/users/"后，它将删除"文件:"，而不会删除"/" 这使我在使用新的FileInputStream打开文件时出现错误. 错误:FileNotFoundException

After using URL.getFile() method which returns String as " /C:/users/ " it removes "file:" only not the "/ " This / gives me a error in opening a file using new FileInputStream. Error : FileNotFoundException

"/"导致获取路径对象时出现相同的问题. 在这里，目录值是从URL.getResource().getFile()

" / " in the starting of the filename causes the same problem in getting the path object. Here , value of directory is retrieved from the URL.getResource().getFile()

路径目标= Paths.get(目录);

Path Dest = Paths.get(Directory);

收到的错误是: java.nio.file.InvalidPathException:索引2处的非法字符<:>:/C:/Users/

有人面对这样的问题吗?

is anyone face such issue ?

推荐答案

不使用URL.getFile()，它返回URL的文件"部分，该部分与文件或文件的路径名不同在磁盘上. (看起来很像，但是您发现有很多不匹配的方法.)相反，调用URL.toURI()并将生成的URI对象传递给Paths.get()

Don't use URL.getFile(), it returns the "file" part of the URL, which is not the same as a file or path name of a file on disk. (It looks like it, but there are many ways in which there is a mismatch, as you have discovered.) Instead, call URL.toURI() and pass the resulting URI object to Paths.get()

只要您的URL指向一个真实文件而不是jar文件中的资源，那该行得通.

That should work, as long as your URL points to a real file and not to a resource inside a jar file.

示例:

URL url = getClass().getResource("/some/resource/path");
Path dest = Paths.get(url.toURI());

这篇关于URL.getFile()中的错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！