如何避免从URL.getFile()获取URL编码的路径? [英] How to avoid getting URL encoded paths from URL.getFile()?

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问题描述

尝试获取给定资源的路径时遇到以下问题:

I'm having the following problem when trying to get the path of a given resource:

    System.out.println("nf="+new File(".").getAbsolutePath());      
    System.out.println("od="+new File(this.getClass().getResource(".").getFile());

我得到的输出是:

nf=C:\Users\current user\workspace\xyz\.
od=C:\Users\current%20user\workspace\xyz\bin\something

问题在于%20 URL编码.如何避免呢?是否有一种直接的方法可以避免一开始就得到这种字符串,还是应该只对返回URL的某些方法运行返回的字符串?

The problem lies with the %20 URL encoding thing. How to avoid it? Is there a direct way to avoid getting this kind of string in the first place, or should I just run the returned string against some method that will do the URL decoding?

谢谢

推荐答案

这归因于API中的URL处理问题.您可以通过以下方法解决此问题:首先将URL字符串转换为URI :

This is due to a URL handling quirk in the API. You can work around this by converting the URL string to a URI first:

new URI(this.getClass().getResource(".").toString()).getPath()

这将产生如下字符串:

"C:\Users\current user\workspace\xyz\bin\something"

这篇关于如何避免从URL.getFile()获取URL编码的路径?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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