日期的JSON序列化策略 [英] JSON serialization strategy for dates

问题描述

我遇到的问题是，我有一些使用Java的使用者和一些使用浏览器的使用者.我的目标浏览器是IE7 +(仅适用于IE7的json3)和& Chrome.

The problem I am having is that I have some consumers that are Java and some that are browsers. My target browsers are IE7+ (json3 for IE7 only) & Chrome.

对于浏览器，我希望将日期反序列化为Date JavaScript对象(使用JSON.parse()方法.对于Java使用者，我希望反序列化为java.util.Date Java对象.

For a browser I wish to have the date deserialize to a Date JavaScript object (using the JSON.parse() method. For a Java consumer I wish to deserialize to a java.util.Date Java object.

鉴于我无法在浏览器端进行任何更改.我必须将消息序列化为这样的内容:

Given that I can't change anything on the browser side. I have to do serialize the messages to something like this:

{ myDate: new Date(<EPOCH HERE>) }

这当然会导致Java解串器出现问题.但是，我希望我可以使用Gson做一些事情来使这项工作...有很多想法吗?

Which of course will cause a problem for Java deserializer. However, I am hoping there is something I can do with Gson to make this work...amy ideas?

还是应该完全采用其他策略?

Or should I take a different strategy altogether?

推荐答案

我通常使用注释@JsonSerialize和@JsonDeserialize来解决此问题.我还使用ISO8601格式作为REST API日期的标准.

I usually use the annotation @JsonSerialize and @JsonDeserialize to deal with this problem. I also use ISO8601 format as a standard for our REST API dates.

@JsonSerialize(using=JsonDateSerializer.class)
@JsonDeserialize(using=JsonDateDeserializer.class)
private Date expiryDate;

JsonDateSerializer 类

@Component
public class JsonDateSerializer extends JsonSerializer<Date>
{
    // ISO 8601
    private static final DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");

    @Override
    public void serialize(Date date, JsonGenerator gen, SerializerProvider provider)
            throws IOException, JsonProcessingException
    {
        String formattedDate = dateFormat.format(date);
        gen.writeString(formattedDate);
    }
}

JsonDateDeserializer 类

@Component
public class JsonDateDeserializer extends JsonDeserializer<Date>
{
    // ISO 8601
    private static final DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");

    @Override
    public Date deserialize(JsonParser jsonParser, DeserializationContext deserializationContext)
            throws IOException, JsonProcessingException
    {
        try
        {
            return dateFormat.parse(jsonParser.getText());
        }
        catch (ParseException e)
        {
            throw new JsonParseException("Could not parse date", jsonParser.getCurrentLocation(), e);
        }
    }
}

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