Java GSON-将int作为字符串序列化为json文件 [英] Java GSON - serialize int as strings to json file

问题描述

我有这个Java类:

class Car {
     int mileage;
     int id;
}

当我告诉gson对其进行序列化时，它当然会将其序列化为:

When I tell gson to serialize it, it of course serializes it to:

{
  "mileage": 123,
  "id": 12345678
}

但是如果我要将其序列化为:

But what if I want to serialize it to:

{
  "mileage": "123",
  "id": "12345678"
}

假设无法将我的成员从int更改为String，是否有办法告诉gson将这些int成员作为字符串序列化到json文件?

Assuming changing my members from int to String, is not an option, is there a way to tell gson to serialize those int members as strings to the json file?

推荐答案

可能有很多方法可以实现您想要的目标. 我将分享两种方式.

There are likely many ways to achieve what you desire. I will share two ways.

第一-使用自定义序列化

秒-使用JsonAdapter注释-更简单

public static class CarSerializer implements JsonSerializer<Car> {
    public JsonElement serialize(final Car car, final Type type, final JsonSerializationContext context) {
        JsonObject result = new JsonObject();
        result.add("mileage", new JsonPrimitive(Integer.toString(car.getMileage())));
        result.add("id", new JsonPrimitive(Integer.toString(car.getId())));

        return result;
    }
}

要调用此代码，只需修改您的代码或将以下代码与构造函数一起使用

To call this, simply adapt your code or use the following code with a constructor

    Car c = new Car(123, 123456789);
    com.google.gson.Gson gson = new 
    GsonBuilder().registerTypeAdapter(Car.class, new CarSerializer())
            .create();
    System.out.println(gson.toJson(c));

输出应为

{"mileage":"123","id":"12345678"}

示例1的完整代码

public class SerializationTest {

    public static class Car {
        public int mileage;
        public int id;
    
        public Car(final int mileage, final int id) {
            this.mileage = mileage;
            this.id = id;
        }

        public int getId() {
            return id;
        }

        public void setId(final int id) {
            this.id = id;
        }

        public String getMileage() {
            return mileage;
        }    

        public void setMileage(final String mileage) {
            this.mileage = mileage;
        }

    }    

    public static class CarSerializer implements JsonSerializer<Car> {
        public JsonElement serialize(final Car car, final Type type, final JsonSerializationContext context) {
        JsonObject result = new JsonObject();
        result.add("mileage", new JsonPrimitive(Integer.toString(car.getMileage())));
        result.add("id", new JsonPrimitive(Integer.toString(car.getId())));

        return result;
    }
}

public static void main(final String[] args) {
    Car c = new Car(123, 123456789);
    com.google.gson.Gson gson = new 
    GsonBuilder().registerTypeAdapter(Car.class, new CarSerializer())
            .create();
    System.out.println(gson.toJson(c));
}

}

在Car类上使用JsonAdapter注释

Use the JsonAdapter Annotation on the Car class

@JsonAdapter(CarAdapter.class)
public class Car {
    public int mileage;
    public int id;
}

创建自定义适配器

public  class CarAdapter extends TypeAdapter<Car> {

    @Override
    public void write(JsonWriter writer, Car car) throws IOException {
        writer.beginObject();

        writer.name("mileage").value(car.getMileage());
        writer.name("id").value(car.getId());  
        writer.endObject();
    }

    @Override
    public Car read(JsonReader in) throws IOException {
        // do something you need
        return null;
    }

}

要使用此方法进行序列化，请使用类似的

To serialize, using this method, use something like this

Car c = new Car(123, 123456789);
Gson gson = new Gson();    
String result = gson.toJson(c);

在这种情况下，应打印result

Printing result in this case should output

{"mileage":"123","id":"12345678"}

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