无法将json转换为Model [英] Can not convert json to Model

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本文介绍了无法将json转换为Model的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有来自url的json.我需要将此json转换为模型

I have json from url. I need Convert This json to Model

{
    "someField": 3,
    "datesField": ["2017-08-19",
    "2017-08-20",
    "2017-08-26",
    "2018-12-30"]
}

我创建了用于映射的模型

I create models for mapping

@Data
@NoArgsConstructor
private class Response{
    @JsonProperty("someField")
    private int someField;
    @JsonProperty("datesField")
    private DatesField datesField;
}

@Data
@NoArgsConstructor
private class DatesField{
    private String[] strings;
}

尝试转换

ObjectMapper mapper = new ObjectMapper();
Dates dates = mapper.readValue(forObject, Response.class);

尝试转换时出现错误:

无法在START_ARRAY之外反序列化packeg.DatesField的实例 令牌

Can not deserialize instance of packeg.DatesField out of START_ARRAY token

推荐答案

根据模型,属性json不正确.在datesField对象中没有datesField类型的数组,而是一个字符串数组.

The json attributed is incorrect according to the model. There is no array of datesField type but an array of strings within the datesField object.

您的对象json等效项应为:

Your object json equivalent shall be:

{
    "someField": 3,
    "datesField": {
        "strings":["2017-08-19",
         "2017-08-20",
         "2017-08-26",
         "2018-12-30"]
     }
}


反之,如果您需要适应json响应,请按照@xenteros的建议将模型更改为:


Or the other way, if you need to adapt to the json response, change your model as suggested by @xenteros to:

@Data
@NoArgsConstructor
private class Response{
    @JsonProperty("someField")
    private int someField;
    @JsonProperty("datesField")
    private String[] datesField;
}


此外,请注意,用于映射响应的Java代码应更改为:


Also, note that the java code to map the response should be changed from:

Dates dates = mapper.readValue(forObject, Response.class);

Response response = mapper.readValue(forObject, Response.class);

这篇关于无法将json转换为Model的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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