迅速的转义控制字符 [英] swift Unescaped control character
本文介绍了迅速的转义控制字符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试从服务器获取json并将其反序列化,但是我尝试使用带有未转义的控制字符的probelas. 我的代码如下...
I'm trying to get a json from a server and deserialize it, but I try probelas with unescaped control characters. My code is as follows ...
let urlFinal = "http://000.0000.000.000:8080"
let jsonUrl = urlFinal
let session = NSURLSession.sharedSession()
let shotsUrl = NSURL(string: jsonUrl)
let task = session.dataTaskWithURL(shotsUrl!) {data, response, error in
guard data != nil else {
falha()
return
}
//let json = JSON(data: data!)
//print(json["ServicoCliente"][0]["id"])
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.MutableContainers )
let J = jsonData as! NSDictionary
print(jsonData)
let us = J["ServicoCliente"]
print(us)
dispatch_async(dispatch_get_main_queue(),{
sucesso()
});
} catch _ {
falha()
}
}
task.resume()
我也使用Alamofire 3.0进行了尝试:
and I also tried this using Alamofire 3.0:
Alamofire.request(.GET, "http://000.000.000.000/", parameters: nil)
.responseJSON { response in
debugPrint(response) // prints detailed description of all response properties
print(response.request) // original URL request
print(response.response) // URL response
print(response.data) // server data
print(response.result) // result of response serialization
if let JSON = response.result.value {
print("JSON: \(JSON)")
}
}
并得到此错误:
字符263周围的转义控制字符
Unescaped control character around character 263
如何删除字符而不进行转义?
How can I remove characters without escape?
我使用X-Code 7.3.1和Swift 2.3
I use X-Code 7.3.1 and Swift 2.3
更新: 杰森
{"ServicoCliente":[{"id":"195","cliente":"247","enderecoFavoritos":"48","servicoProfissional":"194","ind_estado_cliente":"A","ind_estado_profissional":"","profissional_id":"240","profissional_nome":"PetMax","servicotipo_nome":"Petshop","servicosubtipo_nome":"Tosa ","dta_inc_alt":"2016-11-05 22:56:19.333","ind_finalizado":"N"}]}
推荐答案
要解决此问题,必须将数据转换为字符串,删除字符,然后转换为dataonly,然后反序列化
To fix this, you must convert the data for string, remove characters and then convert to dataonly then deserialize
let urlFinal = "http://000.0000.000.000:8080"
let jsonUrl = urlFinal
let session = NSURLSession.sharedSession()
let shotsUrl = NSURL(string: jsonUrl)
let task = session.dataTaskWithURL(shotsUrl!) {data, response, error in
guard data != nil else {
falha()
return
}
var dataToString = String(data: data!, encoding: NSUTF8StringEncoding)
dataToString = stringByRemovingControlCharacters2(dataToString!)
let ndata = dataToString!.dataUsingEncoding(NSUTF8StringEncoding)
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(ndata!, options: NSJSONReadingOptions.MutableContainers )
let J = jsonData as! NSDictionary
print(jsonData)
let us = J["ServicoCliente"]
print(us)
dispatch_async(dispatch_get_main_queue(),{
sucesso()
});
} catch _ {
falha()
}
}
task.resume()
并添加功能
func stringByRemovingControlCharacters2(string: String) -> String {
let controlChars = NSCharacterSet.controlCharacterSet()
var range = string.rangeOfCharacterFromSet(controlChars)
var mutable = string
while let removeRange = range {
mutable.removeRange(removeRange)
range = mutable.rangeOfCharacterFromSet(controlChars)
}
return mutable
}
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