获取具有一定值的json对象的特定部分 [英] Get specific part of json object which has a certain value

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本文介绍了获取具有一定值的json对象的特定部分的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试获取Json的特定部分,但不知道如何做.

I'm trying to get a specific part of Json, but couldn't figure out how.

我的json看起来像:

My json looks like:

[
    {
        "ResourceId":"1",
        "ResourceText":"Hello",
        "LanguageId":"1"
    },
    {
        "ResourceId":"2",
        "ResourceText":"World",
        "LanguageId":"1"
    }
    .
    .
    .
]

因此,例如,我需要零件(根据pResourceId参数进行更改,因此我每次都尝试更改)

So for example I want the part (changes according to pResourceId parameter, so what I'm trying to get changes everytime)

    {
        "ResourceId":"1",
        "ResourceText":"Hello",
        "LanguageId":"1"
    }

但是我听不懂.到目前为止,我尝试过的事情:

But I couldn't get it. What I tried so far:

JObject data = JObject.Parse(jsonStringResources);
return data.Values().Where(x => x.Contains("ResourceId\" : \"" +pResourceId +"\"")  ) as clsResource;

推荐答案

我将为您的JSON格式建立一个模型:

I would make a model for the format of your JSON:

class Model
{
    public string ResourceId { get; set; }
    public string ResourceText { get; set; }
    public string LanguageId { get; set; }
}

然后您可以执行以下操作:

And then you can do:

var models = JsonConvert.DeserializeObject<List<Model>>(jsonStringResources);
var matchingModel = models.Where(model => model.ResourceId == pResourceId).ToList().FirstOrDefault();

return JsonConvert.SerializeObject(matchingModel);

我们将JSON反序列化为我们的模型列表.然后,我们得到ResourceIdpResourceId匹配的模型.最后,我们再次序列化模型以获取JSON字符串.

We deserialize the JSON into a list of our models. We then get the model where the ResourceId matches the pResourceId. Finally, we serialize the model again to get the JSON string.

pResourceId == 1时,结果为:

{
  "ResourceId": "1",
  "ResourceText": "Hello",
  "LanguageId": "1"
}

这篇关于获取具有一定值的json对象的特定部分的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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