映射一定的JSON值枚举值C＃ [英] Mapping a certain JSON value to Enum value C#

问题描述

我创建了堆栈交易所API类。该 filter_object 类型包含成员 FILTER_TYPE 这将是要么安全，不安全或无效。所以，我创建了一个这样的枚举：

I am creating classes for the Stack Exchange API. The filter_object type contains a member filter_type which will be either safe, unsafe, or invalid. So I created an enum like this:

[JsonConverter(typeof(StringEnumConverter))]
public enum FilterType
{
    safe,
    @unsafe, // Here lies the problem.
    invalid
}

由于不安全是一个关键字，我有一些前缀添加到它。但是，我怎么能值不安全自动映射到 @unsafe ？例如JSON：

Since unsafe is a keyword, I had to add some prefix to it. But how can I make the value "unsafe" to automatically map to @unsafe? Example JSON:

{
  "filter": "....",
  "filter_type": "unsafe",
  "included_fields": [
    "...",
    "....",
    "....."
  ]
}

如何反序列化，使得 FILTER_TYPE 自动转换为过滤式。@不安全？

How can I deserialize it, such that the filter_type is automatically converted to FilterType.@unsafe?

更新< /强> - 解决：

Update - Solved:

使用@符号的标识符使得之前有可能是相同的关键字。它的工作原理，即使@会出现在智能感知罚款。

Using the @ symbol before an identifier makes it possible to be the same as keywords. It works fine even though the @ appears in intellisense.

推荐答案

您可以使用JsonProperty，像这样

You can use JsonProperty, like this

public enum FilterType
{
    safe,
    [JsonProperty("unsafe")]
    @unsafe, // Here lies the problem.
    invalid
}

，然后它会正常工作

And then it will work properly

class MyClass
{
    public FilterType filter_type { get; set; } 
}

public class Program
{
    public static void Main()
    {
        var myClass = JsonConvert.DeserializeObject<MyClass>(json);
        var itsUnsafe = myClass.filter_type == FilterType.@unsafe;
        Console.WriteLine(itsUnsafe);
    }

    public static string json = @"{
  ""filter"": ""...."",
  ""filter_type"": ""unsafe"",
  ""included_fields"": [
    ""..."",
    ""...."",
    "".....""
  ]
}";
}

输出是：

The output is:

真正

您可以看到的例子在这里工作：的 https://dotnetfiddle.net/6sb3VY

You can see example working here: https://dotnetfiddle.net/6sb3VY

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