Tensorflow 2.1/Keras-"output_node不在图中"尝试冻结图形时出现错误 [英] Tensorflow 2.1/Keras - "output_node is not in graph" error when trying to freeze graph
问题描述
我正在尝试保存使用Keras创建并保存为.h5文件的模型,但是每次尝试运行Frozen_session函数时都会收到此错误消息: output_node/Identity不在图中
I'm trying to save a model I created using Keras and saved as .h5 file but I get this Error Message everytime I try to run the freeze_session function: output_node/Identity is not in graph
这是我的代码(我正在使用Tensorflow 2.1.0):
This is my code (I'm using Tensorflow 2.1.0):
def freeze_session(session, keep_var_names=None, output_names=None, clear_devices=True):
"""
Freezes the state of a session into a pruned computation graph.
Creates a new computation graph where variable nodes are replaced by
constants taking their current value in the session. The new graph will be
pruned so subgraphs that are not necessary to compute the requested
outputs are removed.
@param session The TensorFlow session to be frozen.
@param keep_var_names A list of variable names that should not be frozen,
or None to freeze all the variables in the graph.
@param output_names Names of the relevant graph outputs.
@param clear_devices Remove the device directives from the graph for better portability.
@return The frozen graph definition.
"""
graph = session.graph
with graph.as_default():
freeze_var_names = list(set(v.op.name for v in tf.compat.v1.global_variables()).difference(keep_var_names or []))
output_names = output_names or []
output_names += [v.op.name for v in tf.compat.v1.global_variables()]
input_graph_def = graph.as_graph_def()
if clear_devices:
for node in input_graph_def.node:
node.device = ""
frozen_graph = tf.compat.v1.graph_util.convert_variables_to_constants(
session, input_graph_def, output_names, freeze_var_names)
return frozen_graph
model=kr.models.load_model("model.h5")
model.summary()
# inputs:
print('inputs: ', model.input.op.name)
# outputs:
print('outputs: ', model.output.op.name)
#layers:
layer_names=[layer.name for layer in model.layers]
print(layer_names)
哪些印刷品:
inputs: input_node
outputs: output_node/Identity
['input_node', 'conv2d_6', 'max_pooling2d_6', 'conv2d_7', 'max_pooling2d_7', 'conv2d_8', 'max_pooling2d_8', 'flatten_2', 'dense_4', 'dense_5', 'output_node']
符合预期(与我训练后保存的模型中的层名称和输出相同).
inputs: input_node
outputs: output_node/Identity
['input_node', 'conv2d_6', 'max_pooling2d_6', 'conv2d_7', 'max_pooling2d_7', 'conv2d_8', 'max_pooling2d_8', 'flatten_2', 'dense_4', 'dense_5', 'output_node']
as expected (same layer names and outputs as in the model I saved after training it).
然后我尝试调用freeze_session函数并保存生成的冻结图:
Then I try call the freeze_session function and save the resulting frozen graph:
frozen_graph = freeze_session(K.get_session(), output_names=[out.op.name for out in model.outputs])
write_graph(frozen_graph, './', 'graph.pbtxt', as_text=True)
write_graph(frozen_graph, './', 'graph.pb', as_text=False)
但我收到此错误:
AssertionError Traceback (most recent call last)
<ipython-input-4-1848000e99b7> in <module>
----> 1 frozen_graph = freeze_session(K.get_session(), output_names=[out.op.name for out in model.outputs])
2 write_graph(frozen_graph, './', 'graph.pbtxt', as_text=True)
3 write_graph(frozen_graph, './', 'graph.pb', as_text=False)
<ipython-input-2-3214992381a9> in freeze_session(session, keep_var_names, output_names, clear_devices)
24 node.device = ""
25 frozen_graph = tf.compat.v1.graph_util.convert_variables_to_constants(
---> 26 session, input_graph_def, output_names, freeze_var_names)
27 return frozen_graph
c:\users\marco\anaconda3\envs\tfv2\lib\site-packages\tensorflow_core\python\util\deprecation.py in new_func(*args, **kwargs)
322 'in a future version' if date is None else ('after %s' % date),
323 instructions)
--> 324 return func(*args, **kwargs)
325 return tf_decorator.make_decorator(
326 func, new_func, 'deprecated',
c:\users\marco\anaconda3\envs\tfv2\lib\site-packages\tensorflow_core\python\framework\graph_util_impl.py in convert_variables_to_constants(sess, input_graph_def, output_node_names, variable_names_whitelist, variable_names_blacklist)
275 # This graph only includes the nodes needed to evaluate the output nodes, and
276 # removes unneeded nodes like those involved in saving and assignment.
--> 277 inference_graph = extract_sub_graph(input_graph_def, output_node_names)
278
279 # Identify the ops in the graph.
c:\users\marco\anaconda3\envs\tfv2\lib\site-packages\tensorflow_core\python\util\deprecation.py in new_func(*args, **kwargs)
322 'in a future version' if date is None else ('after %s' % date),
323 instructions)
--> 324 return func(*args, **kwargs)
325 return tf_decorator.make_decorator(
326 func, new_func, 'deprecated',
c:\users\marco\anaconda3\envs\tfv2\lib\site-packages\tensorflow_core\python\framework\graph_util_impl.py in extract_sub_graph(graph_def, dest_nodes)
195 name_to_input_name, name_to_node, name_to_seq_num = _extract_graph_summary(
196 graph_def)
--> 197 _assert_nodes_are_present(name_to_node, dest_nodes)
198
199 nodes_to_keep = _bfs_for_reachable_nodes(dest_nodes, name_to_input_name)
c:\users\marco\anaconda3\envs\tfv2\lib\site-packages\tensorflow_core\python\framework\graph_util_impl.py in _assert_nodes_are_present(name_to_node, nodes)
150 """Assert that nodes are present in the graph."""
151 for d in nodes:
--> 152 assert d in name_to_node, "%s is not in graph" % d
153
154
**AssertionError: output_node/Identity is not in graph**
我已经尝试过,但是我真的不知道如何解决这个问题,因此我们将不胜感激.
I've tried but I don't really know how to fix this, so any help would be much appreciated.
推荐答案
如果使用Tensorflow版本2.x,请添加:
If you use Tensorflow version 2.x add:
tf.compat.v1.disable_eager_execution()
这应该有效. 我没有检查生成的pb文件,但它应该可以工作.
This should work. I have not checked the resulting pb file, but it should work.
感谢反馈.
编辑:但是,例如此线程,TF1和TF2 pb文件根本不同.我的解决方案可能无法正常运行,或者实际上无法创建TF1 pb文件.
edit: However, following e.g, this thread, the TF1 and TF2 pb files are fundamentally different. My solution might not work properly or actually create an TF1 pb file.
如果您随后遇到
RuntimeError:尝试使用封闭的会话.
RuntimeError: Attempted to use a closed Session.
这可以通过重新启动内核来解决.使用上面的线,您只有一张照片.
This can be solved by restarting the kernel. You have only one shot using the line above.
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