$ lookup结果的计数mongodb [英] count of $lookup result mongodb

问题描述

将mongodb与NodeJS驱动程序配合使用

我有2个收藏集.一个用于部门，另一个用于学生.

I have 2 collections. One for department and other for students.

Deparmtent的样本数据.

Sample data for Deparmtent.

{ 
 "_id" : ObjectId("5a24d20590d3d12155f3094e"), "name" : "CSE", "hod" : 
 "abc", 
 "students" : [ 
  ObjectId("5a2129172c3e542acb78c1f5"),
  ObjectId("5a2129172c3e542acb78c1f7"), 
  ObjectId("5a2129172c3e542acb78c1f9"), 
  ObjectId("5a2129172c3e542acb78c1fb")
 ]
}

{
 "_id" : ObjectId("5a24d20590d3d12155f3094f"), 
 "name" : "IT", 
 "hod" : "xyz", , 
 "students" : [ 
  ObjectId("5a2129172c3e542acb78c1f6"),
  ObjectId("5a2129172c3e542acb78c1f8"), 
  ObjectId("5a2129172c3e542acb78c1fa"),
  ObjectId("5a2129172c3e542acb78c1fc") 
 ] 
}

和学生样本数据

{
    "_id" : ObjectId("5a2129172c3e542acb78c1f4"),
    "rollNumber" : 11,
    "name" : "Thor",
    "branch" : ObjectId("5a24d20590d3d12155f3094e"),
}

这是查询:

aggregate([
   {$lookup: 
     { from: "students", 
       localField: "_id", 
       foreignField: "branch", as: "studentData"
     }
   }
])

查询的输出

[ 
  { _id: 5a24d20590d3d12155f3094e,
    name: 'CSE',
    hod: 'abc',
    studentData: [ [Object], [Object], [Object], [Object], [Object] ] 
  },
  { _id: 5a24d20590d3d12155f3094f,
    name: 'IT',
    hod: 'xyz',
    studentData: [ [Object], [Object], [Object], [Object] ] } 
]

我有两个问题

1. 如何打印完整的学生数据.
2. 如何获取每个部门的StudentData计数

推荐答案

要获取完整的学生数据，您可以执行类似的操作

db.student.aggregate(
        [
            {
            $lookup:
                {
                    from:"department",
                    localField:"branch",
                    foreignField:"_id",
                    as:"branch"
                }
            }
        ]
    )

这会给你这样的东西:

{
    "_id" : 1.0,
    "rollNumber" : 110.0,
    "name" : "Thor",
    "branch" : [ 
        {
            "_id" : 1.0,
            "name" : "CSE",
            "hod" : "abc"
        }
    ]
}

获取每个部门的StudentData计数

db.getCollection('student').aggregate(
    [
        {
        $lookup:
            {
                from:"department",
                localField:"branch",
                foreignField:"_id",
                as:"branch"
            }
        },
        {
            $group:
            {
                _id:"$branch",
                "numOfStudent":{$sum:1},
                "listOfStudents":{$push:"$name"}
            }
        }
    ]
)

这会给你这样的东西:

{
    "_id" : [ 
        {
            "_id" : 2.0,
            "name" : "IT",
            "hod" : "xyz"
        }
    ],
    "numOfStudent" : 1.0,
    "listOfStudents" : [ 
        "Ironman2"
    ]
}
{
    "_id" : [ 
        {
            "_id" : 1.0,
            "name" : "CSE",
            "hod" : "abc"
        }
    ],
    "numOfStudent" : 3.0,
    "listOfStudents" : [ 
        "Thor", 
        "Ironman", 
        "Ironman3"
    ]
}

如果要存储学生的ID而不是他们的姓名，则可以将 $ push:$ name 更改为 $ push:$ _ id .

You can change $push:$name to $push:$_id If you want to store the Ids of students and not their names.

编辑使用部门"集合获得相似的结果:

EDIT Get similar result using "Departments" collection:

db.department.aggregate([
{
    $lookup:
                {
                    from:"student",
                    localField:"students",
                    foreignField:"_id",
                    as:"studentsDetails"
                }
},
{
    $project:{
            _id:0,
            name:"$name",
            hod:"$hod",
            numOfStudents:{$size:"$studentsDetails"},
            students:"$studentsDetails"
        }
}
])

这会给你这样的东西:

{
    "name" : "CSE",
    "hod" : "abc",
    "numOfStudents" : 2,
    "students" : [ 
        {
            "_id" : 1.0,
            "rollNumber" : 110.0,
            "name" : "Thor",
            "branch" : 1.0
        }, 
        {
            "_id" : 3.0,
            "rollNumber" : 111.0,
            "name" : "Ironman2",
            "branch" : 2.0
        }
    ]
}

这篇关于$ lookup结果的计数mongodb的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！