尝试上传文件时“无法更改上传处理程序" [英] 'Cannot alter upload handlers' while trying to upload file

问题描述

我正在尝试使用Django中的uploadhandler上传文件.但是它返回了错误:

I'm trying to upload file using uploadhandler in Django. But it's returning the error:

上传完成后，您无法更改上传处理程序

You cannot alter upload handlers after the upload has been processed

代码:

def upload_form(request):
    if request.method == 'POST':
        outPath = '/opt/workspace/jup2/juppro/uploads/23232'
        if not os.path.exists(outPath):
            os.makedirs(outPath)
        request.upload_handlers.insert(0, ProgressUploadHandler(request, outPath)) # place our custom upload in first position
        upload_file = request.FILES.get('file', None)   # start the upload
        return HttpResponse("uploaded ok")

该代码有什么问题?

推荐答案

在开始上传之前，您必须定义uploadhandler.您可以访问request.POST的那一刻，文件已全部上传到内存或临时文件中.这使得定义上载处理程序毫无意义，因为上载已经完成.

You have to define the uploadhandler before you start uploading. The moment you can access request.POST the file has allready been uploaded to the memory or a temporary file. This makes defining an uploadhandler pointless, as the upload has allready been finished.

Django文档非常清楚何时定义自定义的上载处理程序:您只能在访问request.POST或request.FILES之前修改上载处理程序-在开始上载处理后更改上载处理程序没有任何意义."在不了解您的代码的情况下，我只能猜测，但是我认为将您的代码修改为以下内容就足够了:

Django docs are quite clear about when to define a custom uploadhandler: "You can only modify upload handlers before accessing request.POST or request.FILES -- it doesn't make sense to change upload handlers after upload handling has already started." Without knowing enough about your code i can only guess, but i think it should be enough to modify your code to the following:

def upload_form(request):
    outPath = '/opt/workspace/jup2/juppro/uploads/23232'
    if not os.path.exists(outPath):
        os.makedirs(outPath)
    request.upload_handlers.insert(0, ProgressUploadHandler(request, outPath)) # place our custom upload in first position

    if request.method == 'POST':       
        upload_file = request.FILES.get('file', None)   # start the upload
        return HttpResponse("uploaded ok")

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