如何更改上传文件的文件名？ [英] How to change the filename on uploaded file?

问题描述

我有一个 ImageField（），其中指定了 upload_to 路径。它可以保存到 MEDIA_ROOT url。但是，我想将上传的文件更改为其他文件名。

我应该从forms.py或models.py这样做，还应该覆盖存档功能存档？

forms.py

  class UserAvatarForm（forms.ModelForm）：
 class Meta：
 model = UserProfile 
 fields =（'avatar'，）
 def __init __（self，* args，** kwargs）：
 super（UserAvatarForm，self）.__ init __（* args，** kwargs）
  

解决方案

在 ImageField 头像的rel =nofollow noreferrer> upload_to 。 / p>

通常看起来像

  def upload_to（instance，filename）： 
 import os.path 
＃从原始文件名获取扩展名
 fn，ext = os.path.splitext（filename）
 new_filename = ... 
＃返回新文件名，包括其父目录（基于MEDIA_ROOT）
返回path / {new_filename} {ext} .format（new_filename = new_filename，ext = ext）
  

您可以在 new_filename 行，取决于实例或 filename 或任何其他字符串说得通。甚至可以将该文件命名为instance.pk

I have a ImageField() where I have specified the upload_to path. And it works it saves to the MEDIA_ROOT url. However I want to change the uploaded file to some other filename.

Should I do that from the forms.py or from the models.py, and also should I override the the save function to archive that?

forms.py

class UserAvatarForm(forms.ModelForm):
    class Meta:
        model = UserProfile
        fields = ('avatar',)
    def __init__(self, *args, **kwargs):
        super(UserAvatarForm, self).__init__(*args, **kwargs)

解决方案

Customize it in upload_to of the ImageField avatar directly.

Normally it looks like

def upload_to(instance, filename):
    import os.path
    # get extension from raw filename
    fn, ext = os.path.splitext(filename)
    new_filename = ...
    # return new filename, including its parent directories (based on MEDIA_ROOT)
    return "path/{new_filename}{ext}".format(new_filename=new_filename, ext=ext)

You could introduce new name at the new_filename line, depends on instance or filename or any other strings that makes sense. It's even possible to name the file by instance.pk

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