我在java.lang.NumberFormatException中出错:对于输入字符串:"null" [英] I got error in java.lang.NumberFormatException: For input string: "null"

问题描述

我在我的应用程序中的编辑购物车项目中出现错误.错误是: java.lang.NumberFormatException:对于输入字符串:"null" .i事物错误行 interget.parseInt(" + v.getTag());

i have error in edit cart item in my app.the error is : java.lang.NumberFormatException: For input string: "null".i thing error line interget.parseInt("" + v.getTag());

我的代码:

case R.id.iv_edit_cart_item:
                    FragmentManager fm=getActivity().getSupportFragmentManager();
                    Fragment fragment = new ProductDetailActivity();
                    Bundle bundle = new Bundle();
                    int updatePos = Integer.parseInt("" + v.getTag());
                    bundle.putString("key","update");
                    bundle.putString("product_id", mArrListMyCart.get(updatePos).getmStrProductId());
                    bundle.putString("item_id", mArrListMyCart.get(updatePos).getmStrItemId());

                    getUpdateCartItems();
                    //showAlert("Product id-->" + mArrListMyCart.get(Integer.parseInt(""+v.getTag())).getmStrProductId(), -1);
                    fragment.setArguments(bundle);
                    fm.beginTransaction().replace(R.id.content_frame, fragment).addToBackStack("").commit();
                    break;

如何解决这个问题?

推荐答案

当您尝试将非数字 String 解析为任意类型时，会出现 java.lang.NumberFormatException 像 Integer 或 Double 这样的数字.

The java.lang.NumberFormatException comes when you try to parse a non-numeric String to any Number like Integer or Double.

例如，如果您尝试将"null" 转换为 integer ，则将得到 NumberFormatException .

For example, if you try to convert "null" to an integer then you will get NumberFormatException.

错误线程主"中的异常" java.lang.NumberFormatException:对于输入字符串:"null"专门表示您要解析的字符串不是数字.

The error "Exception in thread "main" java.lang.NumberFormatException: For input string: "null" is specifically saying that the String you receive for parsing is not numeric.

在解析之前，请确保 v.getTag()不为空.

Please ensure v.getTag() is not null before parsing.

String input = v.getTag();

If( null != input ) 
{
  int updatePos = Integer.parseInt("" + input);
}

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