java.lang.NumberFormatException用于将字符串转换为long [英] java.lang.NumberFormatException for converting string to long

问题描述

我正在尝试将字符串转换为long并抛出 NumberFormatException .我认为这根本不超出 long 的范围.

I am trying to convert a string to long and it throws the NumberFormatException. I don't think it is beyond range of long at all.

这是要转换的代码，其中 count_strng 是我要转换为long的字符串. trim()函数没有任何区别.

Here is the code to convert, where count_strng is the String I want to convert to long. trim() function is not making any difference.

long sum_link = Long.parseLong(count_strng.trim());

这是堆栈跟踪.

java.lang.NumberFormatException: For input string: "0.003846153846153846"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Long.parseLong(Long.java:441)
at java.lang.Long.parseLong(Long.java:483)

有人知道这里到底是什么问题吗?

Anyone knows what is the exact issue here?

推荐答案

Long.parseLong()试图将输入字符串解析为 long .在Java中， =长定义为/a>:

Long.parseLong() is trying to parse the input string into a long. In Java, a long is defined such that:

long数据类型是64位二进制补码整数.

The long data type is a 64-bit two's complement integer.

定义了这样的整数:

一个整数(来自拉丁文整数，意思是"whole")是可以写而没有小数部分的数字.

An integer (from the Latin integer meaning "whole") is a number that can be written without a fractional component.

您收到的错误表明您要解析的输入字符串是"0.003846153846153846" ，显然，确实有个小数部分.

The error you are getting shows the input string you are trying to parse is "0.003846153846153846", which clearly does have a fractional component.

如果要解析浮点数，则应使用 Double.parseDouble().

You should use Double.parseDouble() if you want to parse a floating point number.

这篇关于java.lang.NumberFormatException用于将字符串转换为long的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！