无法打开另一个片段的片段 [英] Can't open a fragment from another fragment
本文介绍了无法打开另一个片段的片段的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的 Main2Activity
中有5个片段(家庭,设置,newPost,通知和个人资料).
在 HomeFragment
内部,我有一个 RecyclerView
,其中包含很多帖子视图,每个帖子都包含一个打开"按钮,应该打开一个 PostFragment
.问题是,我只能在populateItemRows()方法的 RecyclerViewAdapter
类中使用 setOnClickListener
,所以当我不能使用 getActivity()
时..
Inside HomeFragment
I have a RecyclerView
with a lot of post views, every post containing a "open" button which should open a PostFragment
. The problem is, I can only use setOnClickListener
in RecyclerViewAdapter
class, in populateItemRows() method, so when I can't use getActivity()
..
HomeFragment:
public class HomeFragment extends Fragment{
private RecyclerView recyclerView;
private RecyclerViewAdapter recyclerViewAdapter;
private boolean isLoading = false;
private ArrayList<String> rowsArrayList = new ArrayList<>();
public View onCreateView(@NonNull LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View root = inflater.inflate(R.layout.fragment_home, container, false);
recyclerView = root.findViewById(R.id.recyclerView);
initAdapter();
initScrollListener();
return root;
}
private void initAdapter() {
recyclerViewAdapter = new RecyclerViewAdapter(getActivity(),2);
recyclerView.setLayoutManager(new LinearLayoutManager(getContext()));
recyclerView.setAdapter(recyclerViewAdapter);
}
private void initScrollListener() {
...
}
private void loadMore() {
...
}
}
RecyclerViewAdapter:
public class RecyclerViewAdapter extends RecyclerView.Adapter<RecyclerView.ViewHolder> {
private final int VIEW_TYPE_ITEM = 0;
private final int VIEW_TYPE_LOADING = 1;
private ArrayList<Post> list = new ArrayList();
private static final String TAG = RecyclerViewAdapter.class.getSimpleName();
private String userId = FirebaseAuth.getInstance().getCurrentUser() != null ? FirebaseAuth.getInstance().getCurrentUser().getUid() : null;
private FirebaseFirestore db = FirebaseFirestore.getInstance();
private Context context;
private User currentUser;
private int type;
public RecyclerViewAdapter(Context context, int type) {
this.context = context;
this.type = type;
if (type == 0) {
myPostsRetriever(context);
} else if (type == 1) {
appliedToPostsRetriever(context);
} else if (type == 2) {
homePostsRetriever(context);
}
}
@NonNull
@Override
public RecyclerView.ViewHolder onCreateViewHolder(@NonNull ViewGroup parent, int viewType) {
...
}
@Override
public void onBindViewHolder(@NonNull RecyclerView.ViewHolder viewHolder, int position) {
if (viewHolder instanceof ItemViewHolder) {
populateItemRows((ItemViewHolder) viewHolder, position);
} else if (viewHolder instanceof LoadingViewHolder) {
showLoadingView((LoadingViewHolder) viewHolder, position);
}
}
private void populateItemRows(ItemViewHolder viewHolder, int position) {
...
viewHolder.itemView.findViewById(R.id.seePostButton).setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Fragment newFragment = new PostFragment();
FragmentTransaction transaction = getActivity().getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.mobile_navigation, newFragment);
transaction.addToBackStack(null);
transaction.commit();
}
});
}
推荐答案
您需要从构造中获取Context对象.
You need Context object from construction.
FragmentTransaction fm = ((AppCompatActivity) context).getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.mobile_navigation, newFragment);
transaction.addToBackStack(null);
transaction.commit();
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