在sqlite中更改列中的值 [英] Change a value in a column in sqlite
问题描述
我需要更新某个表中的列中的值.我尝试了这个:
public void updateOneColumn(String TABLE_NAME,String Column,String rowId,String ColumnName,String newValue){字符串sql ="UPDATE" + TABLE_NAME +"SET" + ColumnName +"=" + newValue +"WHERE" + Column +"=" + rowId;db.beginTransaction();SQLiteStatement stmt = db.compileStatement(sql);尝试{stmt.execute();db.setTransactionSuccessful();}最后{db.endTransaction();}}
我这样称呼这个方法:
db.updateOneColumn(路线图","id_roadmap",id,"sys_roadmap_status_mobile_id","1");
这意味着我想在 问题是什么也没发生.我的错误在哪里? 简便解决方案: 更好的解决方案: I need to update a value in a column from a certain table. I tried this : and I call this method like this : which means that I want to set the value The problem is that nothing happens. Where is my mistake? Easy solution: Better solution:
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sys_roadmap_status_mobile_id
列中设置值 1
.
字符串sql ="UPDATE" + TABLE_NAME +"SET" + ColumnName +"='" + newValue +'WHERE" + Column +"=" + rowId;
ContentValues cv = new ContentValues();cv.put(ColumnName,newValue);db.update(TABLE_NAME,cv,Column +"=?",新的String [] {rowId});
public void updateOneColumn(String TABLE_NAME, String Column, String rowId, String ColumnName, String newValue){
String sql = "UPDATE "+TABLE_NAME +" SET " + ColumnName+ " = "+newValue+" WHERE "+Column+ " = "+rowId;
db.beginTransaction();
SQLiteStatement stmt = db.compileStatement(sql);
try{
stmt.execute();
db.setTransactionSuccessful();
}finally{
db.endTransaction();
}
}
db.updateOneColumn("roadmap", "id_roadmap",id,"sys_roadmap_status_mobile_id", "1");
1
in the column sys_roadmap_status_mobile_id
when id_roadmap = id.
String sql = "UPDATE "+TABLE_NAME +" SET " + ColumnName+ " = '"+newValue+"' WHERE "+Column+ " = "+rowId;
ContentValues cv = new ContentValues();
cv.put(ColumnName, newValue);
db.update(TABLE_NAME, cv, Column + "= ?", new String[] {rowId});