启动Finder窗口并选择了特定文件 [英] Launch Finder window with specific files selected

问题描述

我正在尝试以编程方式从Xcode项目启动OS X Finder窗口.我需要打开一个窗口到一个特定的文件夹，并自动选择该文件夹中的特定文件.

I'm trying to programmatically launch an OS X Finder window from an Xcode project. I need the window to open to a specific folder and have specific files within that folder automatically selected.

这类似于在Finder中显示"；Xcode和相关应用中使用的功能.

This is similar to the "Show in Finder" functionality used in Xcode and related apps.

有人知道如何在Objective-C，Swift，AppleScript或Finder命令行参数中执行此操作吗?

Does anyone know how to do this in either Objective-C, Swift, AppleScript, or Finder command-line parameters?

推荐答案

Objective-C版本:

Objective-C version:

NSArray *fileURLs = [NSArray arrayWithObjects:fileURL1, /* ... */ nil];
[[NSWorkspace sharedWorkspace] activateFileViewerSelectingURLs:fileURLs];

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