将具有任意数量参数的任何函数传递给另一个函数 [英] Passing any function with any number of arguments to another function
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问题描述
我正在尝试创建一个C ++函数,该函数接受带有任意数量参数的任何函数,并将其传递给 std :: thread
来启动带有它的线程.
I am trying to create a C++ function that takes any function with any number of arguments and pass it to std::thread
to start a thread with it.
#include <iostream>
#include <thread>
#define __PRETTY_FUNCTION__ __FUNCSIG__
void runFunctionInThread(void(*f)()) { std::thread t(f); t.join(); }
void runFunctionInThread(void(*f)(int), int value) { std::thread t(f, value); t.join(); }
void runFunctionInThread(void(*f)(int, int), int value1, int value2) { std::thread t(f, value1, value2); t.join(); }
void isolatedFunc1() { std::cout << __PRETTY_FUNCTION__ << "\n"; }
void isolatedFunc2(int value) { std::cout << __PRETTY_FUNCTION__ << " value is " << value << "\n"; }
void isolatedFunc3(int value1, int value2) { std::cout << __PRETTY_FUNCTION__ << " value1+value2 is " << value1 + value2 << "\n"; }
int main() {
runFunctionInThread(&isolatedFunc1);
runFunctionInThread(&isolatedFunc2, 2);
runFunctionInThread(&isolatedFunc3, 3, 3);
}
是否总有一个单一的 runFunctionInThread
函数可用于具有任意数量的参数和任何类型的任何函数?
Is there anyway to create a single runFunctionInThread
function that works for any function with any number of arguments and any type?
推荐答案
Use a variadic template with perfect forwarding of its parameters, eg:
#include <iostream>
#include <thread>
#define __PRETTY_FUNCTION__ __FUNCSIG__
template<class Function, class... Args>
void runFunctionInThread(Function f, Args&&... args) {
std::thread t(f, std::forward<Args>(args)...);
t.detach();
}
void isolatedFunc1() { std::cout << __PRETTY_FUNCTION__ << "\n"; }
void isolatedFunc2(int value) { std::cout << __PRETTY_FUNCTION__ << " value is " << value << "\n"; }
void isolatedFunc3(int value1, int value2) { std::cout << __PRETTY_FUNCTION__ << " value1+value2 is " << value1 + value2 << "\n"; }
int main()
{
runFunctionInThread(&isolatedFunc1);
runFunctionInThread(&isolatedFunc2, 2);
runFunctionInThread(&isolatedFunc3, 3, 3);
}
但是,这是相当多余的,因为 std :: thread
可以直接为您处理此操作,因此您根本不需要 runFunctionInThread()
,例如:
However, this is fairly redundant since std::thread
can handle this directly for you, so you don't need runFunctionInThread()
at all, eg:
int main()
{
std::thread(&isolatedFunc1).detach();
std::thread(&isolatedFunc2, 2).detach();
std::thread(&isolatedFunc3, 3, 3).detach();
}
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