JavaScript对象数组按属性的最小值进行过滤 [英] JavaScript objects array filter by minimum value of an attribute

问题描述

我需要通过"rest"属性的最小值来过滤此对象数组.这是做到这一点的一种方法.还有其他方法吗?

I need to filter this object array by minimum value of 'rest' attribute. This is an one way to do it. Is there any other ways ?

'data'变量是链接函数的结果.还有什么其他方法可以在Math.min()函数中再次调用数据"变量而不会.

'data' variable is a result of chained function. Is there any other way to do this without calling 'data' variable again inside Math.min() function.

let data = 
[ { size: 5, qty: 2, rest: 0 },
  { size: 2, qty: 5, rest: 0 },
  { size: 1, qty: 10, rest: 0 },
  { size: 3, qty: 3, rest: 1 },
  { size: 4, qty: 2, rest: 2 } ]

let result = data.filter(e=> e.rest === Math.min(...data.map(f=>f.rest) ) );
console.log(result);

// result is
//[ { size: 5, qty: 2, rest: 0 },
//  { size: 2, qty: 5, rest: 0 },
//  { size: 1, qty: 10, rest: 0 }]

推荐答案

imo.最简单/最好的解决方案是@CertainPerformance给您的解决方案.

imo. the simplest/best solution is the one @CertainPerformance gave you.

只是想添加具有线性运行时的另一种解决方案(实际上仅在数组上迭代一次)

Just wanted to add another solution with linear runtime (that truly iterates only once over the Array)

let data = [
  { size: 5, qty: 2, rest: 0 },
  { size: 2, qty: 5, rest: 0 },
  { size: 1, qty: 10, rest: 0 },
  { size: 3, qty: 3, rest: 1 },
  { size: 4, qty: 2, rest: 2 } 
];

let result = data.reduce((result, item) => {
  let minRest = result.length? result[0].rest: item.rest;

  if (item.rest < minRest) {
    minRest = item.rest;
    result.length = 0;
  }

  if (item.rest === minRest) {
    result.push(item);
  }

  return result;
}, []);

console.log(result);

@ mathieux51让我有了另一个想法，知道如何在方法链中执行此操作，但是其可读性/清晰度/意图不如其他方法好:

@mathieux51 got me another idea how you can do this inside a method chain, but the readability/clarity/intention is not as good as with the other approaches:

let data = [
  { size: 5, qty: 2, rest: 0 },
  { size: 2, qty: 5, rest: 0 },
  { size: 1, qty: 10, rest: 0 },
  { size: 3, qty: 3, rest: 1 },
  { size: 4, qty: 2, rest: 2 } 
];

let result = data.sort((a, b) => a.rest - b.rest)
                 .filter((item, index, array) => item.rest === array[0].rest);

console.log(result);

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