Typescript:使用Lambda函数从两个数组中查找公共对象 [英] Typescript : Find common objects from two array using Lambda function

问题描述

我正在使用Typescript解决以下问题.我想在列表中搜索对象而不是简单的字母或数字.

I am using Typescript for below problem. I want to search object not simple alphabetic or number in the list.

下面是两个数组.我想在不使用任何第三方库的情况下，在单独的列表中获取常用对象.

Below are the two arrays. I want to get common objects in separate list without using any third party library.

    firstArray = [
           {
               "id": 4,
               "name": "Tata"
           },
           {
               "id": 11,
               "name": "Maruti"
           },
           {
               "id": 14,
               "name": "Mahindra"
           }
        ]

        secondArray = [
           {
               "id": 4,
               "name": "Tata"
           },
           {
               "id": 11,
               "name": "Maruti"
           },
           {
               "id": 15,
               "name": "Hyundai"
           },
           {
               "id": 21,
               "name": "Honda"
           } 
        ]
        
// Get Common Elements
// I am getting blank array as output

        console.log(firstArray.filter(( make ) => secondArray.includes( make)));

有什么功能或方法可以找到commons元素吗?

Is there good function or way to find out commons element?

推荐答案

您可以将 array#filter 与 array#some 一起使用.对于第一个数组中的每个对象，检查另一个数组中是否存在 id 和 name .

You can use array#filter with array#some. For each object in the first array, check if id and name exist in the other array.

const firstArray = [{ "id": 4, "name": "Tata" }, { "id": 11, "name": "Maruti" }, { "id": 14, "name": "Mahindra" } ], 
      secondArray = [{ "id": 4, "name": "Tata" }, { "id": 11, "name": "Maruti" }, { "id": 15, "name": "Hyundai" }, { "id": 21, "name": "Honda" } ],
      result = firstArray.filter(o => secondArray.some(({id,name}) => o.id === id && o.name === name));
console.log(result);

这篇关于Typescript:使用Lambda函数从两个数组中查找公共对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！