如何在Swift脚本中运行终端命令?(例如xcodebuild) [英] How do I run a terminal command in a Swift script? (e.g. xcodebuild)

问题描述

我想用swift替换我的CI bash脚本.我不知道如何调用普通的终端命令，例如 ls 或 xcodebuild

I want to replace my CI bash scripts with swift. I can't figure out how to invoke normal terminal command such as ls or xcodebuild

#!/usr/bin/env xcrun swift

import Foundation // Works
println("Test") // Works
ls // Fails
xcodebuild -workspace myApp.xcworkspace // Fails

---

$ ./script.swift
./script.swift:5:1: error: use of unresolved identifier 'ls'
ls // Fails
^
... etc ....

推荐答案

如果您未在Swift代码中使用命令输出，则只需执行以下操作:

If you don't use command outputs in Swift code, following would be sufficient:

#!/usr/bin/env swift

import Foundation

@discardableResult
func shell(_ args: String...) -> Int32 {
    let task = Process()
    task.launchPath = "/usr/bin/env"
    task.arguments = args
    task.launch()
    task.waitUntilExit()
    return task.terminationStatus
}

shell("ls")
shell("xcodebuild", "-workspace", "myApp.xcworkspace")

已更新:适用于Swift3/Xcode8

Updated: for Swift3/Xcode8

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