VSCode:如何在每个终端打开后运行命令? [英] VSCode: How to run a command after each terminal open?

问题描述

在 Windows 上，我必须在打开的每个新终端会话上运行命令 start-ssh-agent.cmd.我的开发环境是VSCode，每天新开十几个终端.每个终端打开后，我必须手动运行这个命令.

On Windows I have to run the command start-ssh-agent.cmd on each new terminal session I open. My development environment is VSCode, and I open a dozen new terminals each day. After each terminal open, I have to manually run this command.

有没有办法在每次打开终端时在终端上运行这个命令?

Is there is a way to run this command on the terminal each time I open one ?

这可能采用 VSCode 扩展、VSCode 配置(设置)或 Windows 环境配置的形式.

This may take the form of a VSCode extension, VSCode configuration (settings) or a Windows environment configuration.

有什么想法吗?

推荐答案

在 Linux 系统上你应该使用:

On Linux systems you should use:

"terminal.integrated.shellArgs.linux"

在 Windows 和 OSX 上:

On Windows and OSX:

terminal.integrated.shellArgs.windows

和

terminal.integrated.shellArgs.osx

分别.

如果您想在每个工作区的基础上应用 shellArgs 设置 - 您可以，尽管 文档 说:

If you want to apply shellArgs setting on a per-workspace basis - you can, despite the fact that documentation says:

第一次打开定义任何这些设置的工作区时，VS Code 会警告您，并且随后总是忽略这些值之后

The first time you open a workspace which defines any of these settings, VS Code will warn you and subsequently always ignore the values after that

至少 1.42 版的 VSCode 会问你类似的问题:

At least version 1.42 of VSCode asks you something like:

这个工作区想要设置shellArgs，你要允许吗?"

"This workspace wants to set shellArgs, do you want to allow it?"

参见问题 19758

在 Linux 上，如果您使用 bash(VSCode 中 shell 的默认设置)，则有一些微妙之处:

On Linux, if you are using bash (default for shell in VSCode), there are some subtleties:

"terminal.integrated.shellArgs.linux": ["your_init_script.sh"]

将执行脚本并立即关闭终端.为了防止这种情况，您必须使用 $SHELL 命令结束脚本.

will execute the script and close terminal right away. To prevent this you'll have to end the script with $SHELL command.

#!/bin/bash
echo "init"
export PATH=$PATH:/xxx/yyy/zzz # or do whatever you want
$SHELL

但是那样你最终会进入一个子shell.有时这是不可接受的 (阅读 1) (阅读 2).

But that way you end up in a subshell. Sometimes it's unacceptable (Read 1) (Read 2).

"terminal.integrated.shellArgs.linux": ["--init-file", "your_init_script.sh"]

将使您留在初始 shell，但不会执行 .bashrc init 文件.所以你可能想在 your_init_script.sh 里面 source ~/.bashrc

will leave you in the initial shell, but will not execute the .bashrc init file. So you may want to source ~/.bashrc inside your_init_script.sh

#!/bin/bash
source ~/.bashrc
echo "init"
export PATH=$PATH:/xxx/yyy/zzz # or do whatever you want

如果您已经在存储库中拥有 some_init_script.sh，并且出于某种原因不想将 source ~/.bashrc 添加到其中，您可以使用这:

And if you already have some_init_script.sh in a repository, and for some reason don't feel like adding source ~/.bashrc into it, you can use this:

"terminal.integrated.shellArgs.linux": ["--init-file", "your_init_script.sh"]

your_init_script.sh:

#!/bin/bash
source ~/.bashrc
source some_init_script.sh

some_init_script.sh:

#!/bin/bash
echo "init"
export PATH=$PATH:/xxx/yyy/zzz # or do whatever you want

<小时>在 VSCode 之外，您无需创建额外的文件即可完成.像这样

bash --init-file <(echo "source ~/.bashrc; source some_init_script.sh")

但我无法将此字符串传递到 terminal.integrated.shellArgs.linux - 它需要以某种方式拆分为数组.我尝试过的所有组合都没有奏效.

But I could not pass this string into terminal.integrated.shellArgs.linux - it needs to be split into array somehow. And none of the combinations I've tried worked.

<小时>

此外，您可以在特定文件夹中打开终端:

---

Also, you can open terminal at a specific folder:

terminal.integrated.cwd

更改环境:

"terminal.integrated.env.linux"
"terminal.integrated.env.windows"
"terminal.integrated.env.osx"

甚至可以根据自己的喜好更改终端

And even change terminal to your liking with

terminal.integrated.shell.linux
terminal.integrated.shell.windows
terminal.integrated.shell.osx

或

terminal.external.linuxExec
terminal.external.osxExec
terminal.external.windowsExec

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