如何用ASCII替换Unicode字符 [英] How to replace Unicode characters with ASCII

问题描述

我有以下命令将Unicode字符替换为ASCII字符.

I have the following command to replace Unicode characters with ASCII ones.

sed -i 's/Ã/A/g'

问题是在我的Unix环境中，sed命令无法识别Ã，因此我假设您将其替换为十六进制值.如果我改用 C3 ，语法会是什么样?

The problem is Ã isn't recognized by the sed command in my Unix environment so I'd assume you replace it with its hexadecimal value. What would the syntax look like if I were to use C3 instead?

我正在使用此命令作为其他字符的模板，我想用空格替换这些字符，例如:

I'm using this command as a template for other characters i'd like to replace with blank spaces such as:

sed -i's/©//g'

sed -i 's/©/ /g'

推荐答案

可以在"sed"中使用十六进制值.

It is possible to use hex values in "sed".

echo "Ã" | hexdump -C
00000000  c3 83 0a                                          |...|
00000003

好的，那个字符是两个字节的组合"c3 83".让我们用单字节"A"代替它:

Ok, that character is two byte combination "c3 83". Let's replace it with single byte "A":

echo "Ã" |sed 's/\xc3\x83/A/g'
A

说明:\ x表示"sed"后面跟随有十六进制代码.

Explanation: \x indicates for "sed" that a hex code follows.

这篇关于如何用ASCII替换Unicode字符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！