xargs仅使用内置函数 [英] xargs just working with built in functions

问题描述

我正在尝试加快数据库的处理速度.我向xargs迁移.但是我被严重卡住了.如果xargs调用的命令不是内置命令，则无法向xargs传递参数列表.我不知道原因.这是我的代码:

I am trying to speed up the processing of a database. I migrated towards xargs. But I'm seriously stuck. Piping a list of arguments to xargs does not work if the command invoked by xargs isn't a built in. I can't figure out why. Here is my code:

#!/bin/bash

list='foo
bar'

test(){
    echo "$1" 
}

echo "$list" | tr '\012' '\000' | xargs -0 -n1 -I '{}' 'test' {}

所以根本没有输出.测试功能永远不会执行.但是，如果我将"xargs"命令中的"test"替换为"echo"或"printf"，则效果很好.

So there is no output at all. And test function never gets executed. But if I replace "test" in the "xargs" command with "echo" or "printf" it works fine.

推荐答案

xargs将可执行文件作为参数(包括自定义脚本)而不是环境中定义的函数.

xargs takes an executable as an argument (including custom scripts) rather than a function defined in the environment.

将代码移至脚本或使用 xargs 将参数传递给外部命令.

Either move your code to a script or use xargs to pass arguments to an external command.

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