如何使用＆GT;在xargs命令？ [英] How to use > in an xargs command?

问题描述

我想找到一个bash命令，可以让我用grep每个文件在目录和grep的输出写入到一个单独的文件。我的猜测是一直在做这样的事情。

I want to find a bash command that will let me grep every file in a directory and write the output of that grep to a separate file. My guess would have been to do something like this

ls -1 | xargs -I{} "grep ABC '{}' > '{}'.out"

不过，据我所知，xargs的不喜欢双引号。如果我删除了双引号，但是，那么命令会将整个命令到名为{}。出来，而不是一系列单个文件的单个文件的输出。

but, as far as I know, xargs doesn't like the double-quotes. If I remove the double-quotes, however, then the command redirects the output of the entire command to a single file called '{}'.out instead of to a series of individual files.

有谁知道的一种方式做到这一点使用xargs的？我只是用这个grep的场景为例来说明xargs的，因此任何解决方案，不使用的xargs并不适用于我，我的问题。

Does anyone know of a way to do this using xargs? I just used this grep scenario as an example to illustrate my problem with xargs so any solutions that don't use xargs aren't as applicable for me.

推荐答案

不要让这样的错误：

sh -c "grep ABC {} > {}.out"

这将在很多条件打破，包括时髦的文件名和不可能引用的权利。你需要做的，这是什么：

This will break under a lot of conditions, including funky filenames and is impossible to quote right. What you need to do, is this:

sh -c 'grep ABC "$1" > "$1.out"' -- {}

适用于的xargs 以及找到。

顺便说一句，从来不使用xargs的，而不 -0 选项（除非非常罕见的，控制一次性交互使用你在哪里不担心破坏你的数据）。

By the way, never use xargs without the -0 option (unless for very rare and controlled one-time interactive use where you aren't worried about destroying your data).

另外，不要解析 LS 。永远。用匹配或找到而不是： http://mywiki.wooledge.org/ParsingLs

Also don't parse ls. Ever. Use globbing or find instead: http://mywiki.wooledge.org/ParsingLs

使用找到对于需要递归和一个简单的循环与一切一水珠的一切：

Use find for everything that needs recursion and a simple loop with a glob for everything else:

find /foo -exec sh -c 'grep "$1" > "$1.out"' -- {} \;

或非递归

for file in *; do grep "$file" > "$file.out"; done

注意正确使用引号。

Notice the proper use of quotes.

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