有什么方法可以获取匹配的图案线的行号? [英] Are there any ways to obtain the line number of the matched pattern line?

问题描述

例如，一个文本文件具有:

For example , A text file has:

dfsdfsd
f
dsf
dsf
dsf
dsf
sdafadfdasfdsfd
sf
sdfasdfdasfdsfsdf
sd
fsdfdsaf

然后，我想找到一种方法来获取sf的行号并在科幻小说之前插入一段

Then , i would like to find a way to obtain the line number of sf and insert a paragraph before sf

在bash编程中有什么方法可以实现吗?

Are there any ways to doing it in bash programming ???thanks

推荐答案

如果要查找行号，可以使用 grep -n .

If you want to find out the line number, you could use grep -n.

如果只想在前一行插入一行，则可以使用 sed 像这样:

If you just want to insert a line on the preceding line, you could use sed like this:

sed "s/sd/paragraph\nsd/" file

这将在"sd"行上方插入文本"paragraph".

This will insert the text "paragraph" above the line with "sd".

仅在第一个比赛中执行此操作:

To only do this for the first match:

sed "0,/sd/ { s/sd/paragraph\nsd/ }" file

在这里，我们只匹配行，直到第一个匹配的"sd"为止，因此以后的所有sd都将不匹配.

Here, we only match lines until the first matching "sd", so any later sd's will not match.

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