Java Runtime exec()无法正常工作 [英] Java Runtime exec() not working

问题描述

我尝试通过 java 这样执行shell命令

I try to execute a shell command via java like this

if (Program.isPlatformLinux())
{
    exec = "/bin/bash -c xdg-open \"" + file.getAbsolutePath() + "\"";
    exec2 = "xdg-open \"" + file.getAbsolutePath() + "\"";
    System.out.println(exec);
}
else
{
    //other code
}
Runtime.getRuntime().exec(exec);
Runtime.getRuntime().exec(exec2);

但是什么也没有发生.当我执行此代码时，它将在控制台中输出/bin/bash -c xdg-open"/home/user/Desktop/file.txt" ，但不会打开文件.我也尝试过先调用bash，然后再调用 xdg-open -命令，但是没有改变.

but nothing happens at all. When I execute this code it prints /bin/bash -c xdg-open "/home/user/Desktop/file.txt" in the console, but does not open the file. I have also tried to call the bash first and then the xdg-open-command, but there is not change.

这是什么问题，我该如何解决?

What's the problem here and how can I solve this?

调用的输出如下所示:

xdg-open"/home/user/Desktop/files/einf in a- and b/allg fil/ref.txt"xdg-open:意外参数'in'

xdg-open "/home/user/Desktop/files/einf in a- und b/allg fil/ref.txt" xdg-open: unexpected argument 'in'

但这对我来说似乎很奇怪-为什么即使在整个路径都用引号引起来的情况下，为什么在 in 之前将命令分开呢?

But this seeems very strange to me - why is the command seperatet before the in even the entire path is set in quotation marks?

推荐答案

请注意，您无需 xdg-open 即可执行此操作.您可以使用与Java平台无关的桌面 API:

Please note that you don't need xdg-open to do this. You can use the java platform-agnostic Desktop API:

if(Desktop.isDesktopSupported()) {
    Desktop.open("/path/to/file.txt");
}

---

更新

如果标准方法仍然存在问题，则可以将参数作为数组传递，因为 Runtime.exec 不会调用外壳程序，因此不支持或不允许使用引号或转义符:

If the standard approach still gives issues, you can pass the parameters as an array since Runtime.exec does not invoke a shell and therefore does not support or allow quoting or escaping:

String program;
if (Program.isPlatformLinux())
{
    program = "xdg-open";
} else {
    program = "something else";
}

Runtime.getRuntime().exec(new String[]{program, file.getAbsolutePath()});

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