将sed与regex和( [英] Use sed with regex and (

问题描述

我在php文件中有一个功能:

I have a function in php file:

_t('', 'Award received')

我制作了一个正则表达式，它找到了函数_t(''

I've made a regex, which finds first part of the function _t(''

查看正则表达式的作用

现在，我想将该功能替换为其他功能(实际上，我想向该功能添加参数).

Now, I want to replace that function with something else (actually, I want to add argument to the function).

从控制台:

grep -rl "_t('', 'Award received')" application | xargs sed -i "s/_t\s*\(\s*['|\"](\s*\s*)['|\"]/test/g"

Sed不想进行替换，它说:((或(不带一对)，因此看起来它正在尝试在正则表达式中寻找括号...

Sed doesn't want to make replacement, it says: "( or ( without a pair", so it looks like it is trying to look for bracket inside regex...

如何将sed与包含方括号的正则表达式一起使用?

How can I use sed with regex expressions containing brackets?

我有要替换的测试字符串:

I have test string which I want to replace:

_t('124', 'Test')

当我进行简单替换时

sed -i -E 's/124JHGJH/124/g'

它工作正常.

但是，如果我尝试用括号等替换整个字符串，它只会挂出并且没有响应...

But if I try to replace whole string, with parenthesis and other, it just hangs out and not responding...

sed -i -E 's/_t\(\'124JHGJH\'/124/g'

推荐答案

请注意sed正则表达式中 \(和()之间的区别.

Take note of the difference between \( and ( in sed regex.

要在函数调用的最后添加新参数:

To add a new parameter at then end of the function call:

echo "_t('', 'Award received')" | sed 's/_t([^)]\+/&, new_param/'

_t('', 'Award received', new_param)

正则表达式为:

• -t( =文字字符
• [^)] \ + =一个或多个非<)字符

• -t( = literal characters
• [^)]\+ = one or more non-) characters

下一个字符将是函数的关闭括号，因此我假设您要在其中插入新参数.我在替换中使用& 将与正则表达式匹配的文本放在其位置.

The next character will be the function's close paren, so that's where I assume you want to insert the new parameter. I use & in the replacement to put the text matched by the regex in its place.

如果存在一个包含紧密括号字符的文字字符串参数，这将中断.

This will break if there's a literal sting argument that contains a close paren character.

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