php shell exec的作用与直接运行命令不同 [英] php shell exec acting different to running command directly

问题描述

我有一个php脚本，试图从目录结构中删除所有文件，但将所有内容保留在svn中.我在线上找到了此命令，如果直接将其插入外壳，则可以完美地完成工作

I have a php script that attempts to remove all files from a directory structure, but preserve everything in svn. I found this command online which does the job perfectly if you plug it directly in a shell

find /my/folder/path/ -path \'*/.svn\' -prune -o -type f -exec rm {} +

不幸的是，如果我在php上执行命令shell_exec像这样:

Unfortunately if I perform a shell_exec in php on that command like so:

$cmd = 'find $folderPath -path \'*/.svn\' -prune -o -type f -exec rm {} +';
shell_exec($cmd);

然后，我从中调用php脚本的当前目录中的所有文件也将被删除.

Then all the files in my current directory that I call the php script from are deleted as well.

有人可以解释原因，以及如何解决此问题，以便我可以修复php脚本，使其行为如预期的那样，仅删除指定文件夹中的那些文件

Can someone explain why, and how to fix the issue so that I can fix the php script so it acts like expected, removing only those files in the specified folder

下面是完整的源代码，以防万一我错过了一个愚蠢的错误:

The full source code is below, just in case there is perhaps a silly mistake in there that I have missed:

<?php

# This script simply removes all files from a specified folder, that aren't directories or .svn 
# files. It will see if a folder path was given as a cli parameter, and if not, ask the user if they 
# want to remove the files in their current directory.

$execute = false;

if (isset($argv[1]))
{
    $folderPath = $argv[1];
    $execute = true;
}
else
{
    $folderPath = getcwd();
    $answer = readline("Remove all files but not folders or svn files in $folderPath (y/n)?" . PHP_EOL);

    if ($answer == 'Y' || $answer == 'y')
    {
        $execute = true;
    }
}

if ($execute)
{
    # Strip out the last / if it was given by accident as this can cause deletion of wrong files
    if (substr($folderPath, -1) != '/')
    {
        $folderPath .= "/";
    }

    print "Removing files from $folderPath" . PHP_EOL;
    $cmd = 'find $folderPath -path \'*/.svn\' -prune -o -type f -exec rm {} +';
    shell_exec($cmd);
}
else
{
    print "Ok not bothering." . PHP_EOL;
}

print "Done" . PHP_EOL;

?>

推荐答案

您的命令看起来还不错.至少在外壳中.如果您实际上可以通过简单的方法在PHP中解决问题，

Your command looks okay. At least in shell. If you would actually troubleshoot your issue in PHP with a simple

var_dump($cmd);

您会看到错误所在:

$cmd = 'find $folderPath -path \'*/.svn\' -prune -o -type f -exec rm {} +';

仔细观察.提示:一个人不能赚一美元..

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