在显示实时输出的功能中执行命令 [英] Execute a command in a function displaying real-time output

问题描述

在某些Bash脚本中，我正在以这种方式执行一些保留实时输出的命令:

In some Bash scripts I am executing some commands preserving the real-time output in this way:

exec 5>&1
output=$(ls -1 2>&1 |tee /dev/fd/5; exit ${PIPESTATUS[0]})
status=$?

我将这段代码移到一个函数中，以使其可重用，如下所示:

I moved this piece of code in a function to make it reusable like this:

execute() {
    # 1 - Execute backup
    echo "Executing command 'very_long_command'..."
    exec 5>&1
    cmd="very_long_command"
    output=$($cmd 2>&1 |tee /dev/fd/5; exit ${PIPESTATUS[0]})
    status=$?
    echo $output
    echo "very_long_command exited with status $status."
    return $status
}

当我使用 exec_output ="$(execute)" 调用该函数时，我当然可以获取其输出，但是我仍然需要获取 very_long_command 的输出.>在执行过程中，而不是在唯一输出末尾.

When I call the function with exec_output="$(execute)" I can of course get its output, but what I still need is to get the output of very_long_command during its execution, and not at the end in a unique output.

您能帮助我实现这一目标吗?

Could you help me to achieve this?

推荐答案

感谢 @Charles Duffy 我解决了我的问题，将FD 5重定向到stderr:

Thanks to @Charles Duffy I solved my problem, redirecting FD 5 to stderr:

execute() {
    exec 5>&2
    output=$(ls -1 2>&1 | tee /dev/fd/5; exit ${PIPESTATUS[0]})
    status=$?
    echo "$output"
    return $status
}

output="$(execute)"
echo "Function output:"
printf "%s\n" "$output"

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