Bash:如何引用名称中包含另一个变量的变量? [英] Bash: How to reference a variable that contains another variable in its name?

问题描述

我有一个运行变量，假设当前迭代的值是 INDEX = 1122 .我已经导出:

I have a running variable, let's say it value is INDEX = 1122 for the current iteration. I have exported:

导出PRO"$ INDEX" =/some/fancy/dirry

现在，我想引用此变量，但如果这样做:

Now I want to reference to this variable, but if I do:

echo $"PRO $ INDEX"

我得到:

PRO1122

相反，我想看看:

/some/fancy/dirry

非常类似于 echo $ PRO1122 的结果.

但是，我当然不能在循环中对值 1122 进行硬编码.

However, I cannot of course hard code the value 1122 in the loop.

推荐答案

BASH已经具有变量引用机制.

BASH already has a variable reference mechanism.

您可以这样做:

v="PRO$INDEX"
echo "${!v}"
/some/fancy/dirry

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