使用变量作为一个bash脚本另一个变量？ [英] Using a variable as another variable in a bash script?
问题描述
我还挺新的bash脚本，而不是当谈到写我自己的脚本非常技术性的，我有一个脚本，在终端完美。我想用的zenity使事情变得漂亮和简单和直接的（也可作为一个小的学习项目）。
Hi I'm kinda new to bash scripting and not very technical when it comes to writing my own scripts, I have a script that works perfectly in a terminal. I wanted to use zenity to make things nice and simple and straight forward (but also as a little learning project).
该脚本生成随机密码和的zenity是一个相当不错的小工具。
The script generates random passwords and with zenity is quite a good little tool.
我遇到了一个问题，虽然，运行脚本以及一个GUI，但是当我想介绍供用户选择密码的长度某种程度上，它未能出示密码。
在code，让用户输入自己想要的号码（密码的长度）：
I have run into a problem though, the script runs well as a GUI but when I wanted to introduce a way for the user to choose the length of the password it fails to produce the password. The code to let the user input their desired number (length of password) :
number=32
zenity --entry --text="Please enter a number (no limitations!) :" --entry-text="$number"
read newnumber
[ -n "$newnumber" ] && number=$newnumber
其中，如果在终端运行显示终端，但不是在一个盒子的zenity输入的号码。我不能使用变量...
Which, if run in a terminal displays the number entered in the terminal but not in a zenity box. I cannot use the variable...:
number=$newnumber
......后来根据需要像这样的剧本，我从改变一个变量
LENGTH="32"
To :要：
The script runs normally (except not producing a password) as a GUI, but in the terminal I get (if the user entered the number 25) :脚本正常运行（除了不产生一个口令），为图形用户界面，但在终端我得到（如果用户输入的号码25）：
25
/home/server/Desktop/passwd32gen: line 22: [: : integer expression expected
So it's the fact I've used $newnumberas the value in the LENGTH= variable that has broken the generating part of the script. I have tried various different ways to solve this on my own but know too much, I would assume it will be quite a simple missing piece of syntax (or maybe I just hope so).所以这是我用事实 $ newnumber 如的值length = 变量打破脚本的生成部分。我曾尝试过各种不同的方法来解决这个问题对我自己的，但知道得太多了，我会以为这将是一个非常简单的缺失的那一块语法（或者也许我只是希望如此）。
Now I'm at my wits end trying to figure it out, I've tried
现在我在我无计可施试图算起来，我已经试过
declare
and 和
in a number of ways but they just seemed to break the script.在许多方面，但他们只是似乎破坏脚本
Thankyou in advance to anyone who can help in anyway!
三江源提前任何人谁可以帮助反正在！
And please keep in mind I'm looking for a way to use zenity to allow a user to choose the length of the password being generated.
和请记住，我正在寻找一种方式来使用的zenity允许用户选择所生成的密码长度。
The whole script is :
整个脚本是：
推荐答案
如果你真的想能够显示的特殊字符，你可以使用的zenity --text-信息，如下图所示。这不是因为美观，但它可以做到的。
If you REALLY want to be able to display the special characters, you can use zenity --text-info as shown below. It's not as aesthetically pleasing, but it can be done.
又一个2¢
echo "Here is your random $newnumber character password, you can copy and paste it wherever you wish...
$PASS
The passwords generated by this application are very strong, here are the numbers;
Length: $newnumber characters
Character Combinations: 96
Calculations Per Second: 4 billion
Possible Combinations: 2 vigintillion
Based on an average Desktop PC making about 4 Billion calculations per second
It would take about 21 quattuordecillion years to crack your password.
As a number that's 21,454,815,022,336,020,000,000,000,000,000,000,000,000,000,000 years!" | zenity --text-info --title "Your $newnumber character password" --width 600 --height 500`
补遗，
摆弄它多一些后，似乎的zenity不喜欢打印变量包含特殊字符。
After playing with it some more, it appears that zenity doesn't like printing variables with special characters.
我做了2变化。
1 newnumber =`的zenity ....这将读取的zenity输入。
1 newnumber=`zenity.... This will read the input from zenity.
2移除了MATRIX一些特殊字符
2 Removed some special characters from the MATRIX
我打上#CHANGED所有更改
I marked all changes with #CHANGED
下面是修改后的脚本。
#!/bin/bash
# May need to be invoked with #!/bin/bash2 on older machines.
#
#Random 32 character password generator
#
zenity --info --title="32 Character Password Generator" --text="Hi, so you want to get yourself a new password? You've the perfect little application here, just click OK to generate your new password."
number=32
# CHANGED
newnumber=`zenity --entry --text="Please enter a number (no limitations!) :" --entry-text="$number"`
# read newnumber
[ -n "$newnumber" ] && number=$newnumber
#CHANGED Removed offending special characters
MATRIX="0123456789?_+-!$%^>ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
# Password will consist of standard characters.
LENGTH="$newnumber"
#This variable can be changed for password lenth
#(need to try get zenity to let user choose that number)
while [ "${n:=1}" -le "$LENGTH" ]
# := is "default substitution" operator.
# So, if 'n' has not been initialized, set it to 1.
do
PASS="$PASS${MATRIX:$(($RANDOM%${#MATRIX})):1}"
# Very clever, but tricky.
# Starting from the innermost nesting...
# ${#MATRIX} returns length of array MATRIX.
# $RANDOM%${#MATRIX} returns random number between 1
# and [length of MATRIX] - 1.
# ${MATRIX:$(($RANDOM%${#MATRIX})):1}
# returns expansion of MATRIX at random position, by length 1.
# See {var:pos:len} parameter substitution in Chapter 9.
# and the associated examples.
# PASS=... simply pastes this result onto previous PASS (concatenation).
# to let zenity show the password being built one character at a time, uncomment the following line
# zenity --info --text="$PASS"
let n+=1
# Increment 'n' for next pass.
done
# CHANGED $PASS to '$PASS' below
zenity --info --title="Your 32 character password" --text="Here is your random 32 character password, you can copy and paste it wherever you wish...
$PASS
The passwords generated by this application are very strong, here are the numbers;
Length: 32 characters
Character Combinations: 96
Calculations Per Second: 4 billion
Possible Combinations: 2 vigintillion
Based on an average Desktop PC making about 4 Billion calculations per second
It would take about 21 quattuordecillion years to crack your password.
As a number that's 21,454,815,022,336,020,000,000,000,000,000,000,000,000,000,000 years!" # you could redirect to a file, to store the password. Use something like $PASS 2> /file/name
exit 0
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