从Bash或Ruby创建有效的JSON字符串? [英] Create a valid JSON string from either Bash or Ruby?

问题描述

我想在 DigitalOcean 中创建20个小滴，并希望从Bash或Ruby.Bash起初似乎是最简单的，但是后来我发现JSON对于引号非常挑剔，并要求 -d 参数具有单引号.

I would like to create 20 droplets in DigitalOcean, and would like to do it from either Bash or Ruby. Bash seemed at first to be the easiest, but then I turned out JSON is super picky about quotes and demands the -d argument to have single quotes.

所以我下面的脚本不会扩展 $ line 变量=(

So my script below doesn't expand the $line variable =(

问题

所以现在我在想，如果我使用Ruby完全有帮助吗?我会不会再遇到同样的问题，只是换一种语言?

So now I am thinking, would it at all help if I used Ruby? Wouldn't I end up in the same problem again, just in another language?

token=123

while read line; do
  curl -qq -X POST -H "Content-Type: application/json" -H "Authorization: Bearer $token" -d '{"name":"02267-$line","region":"fra1","size":"s-2vcpu-4gb","image":"ubuntu-18-04-x64","ssh_keys":["14063864","22056139","23743266"],"backups":false,"ipv6":false,"user_data":null,"private_networking":null,"volumes": null,"tags":["02267-$line"]}' "https://api.digitalocean.com/v2/droplets"
done < list.txt

list.txt

tokyo
seoul
osaka
kobe

推荐答案

使用 jq 之类的工具为您生成正确的JSON.

Use a tool like jq to generate correct JSON for you.

# Note: $x here is *not* a shell variable, but a jq variable
# that jq will expand, ensuring the value is correctly quoted.
filter='{name: "02267-\($x)",
         region: "fra1",
         size: "s-2vcpu-4gb",
         image: "ubuntu-18-04-x64",
         ssh_keys ["14063864","22056139","23743266"],
         backups: false,
         ipv6: false,
         user_data: null,
         private_networking: null,
         volumes: null,
         tags: ["02267-\($x)"]
       }'

jq -n --argjson x "$line" "$filter" |
  curl -qq -X POST \
     -H "Content-Type: application/json" \
     -H "Authorization: Bearer $token" \
     -d @- \
     "https://api.digitalocean.com/v2/droplets"

这篇关于从Bash或Ruby创建有效的JSON字符串?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！