无法创建有效的nsurl [英] Not able to create valid nsurl

问题描述

我正在尝试从xml Web服务解析数据，但无法获取我的URL.请检查我的代码:

I am trying to parse data from a xml web service but I am not able to get my url. Please check my code:

NSLog(@"log url: %@",url);
[url stringByAddingPercentEscapesUsingEncoding: NSASCIIStringEncoding];
NSLog(@"%@",url);
[url stringByReplacingOccurrencesOfString:@" " withString:@"%20"];
NSLog(@"%@",url);

NSURL *URL = [NSURL URLWithString:url];
NSXMLParser *home_Parser = [[NSXMLParser alloc] initWithContentsOfURL:URL];
[home_Parser setDelegate:self];
[home_Parser parse];
[home_Parser release];  

我总是将URL设为nil.原因是我的字符串url包含空格.我试图替换它并逃脱它，但是它不起作用.以下是我正在使用的网址

I am always getting URL as nil. The reason is my string url has space included. I have tried to replace it and escape it but it is not working. Following is the url that I am using

http://www.mydomain.com/radioListGenre.php?genre=Radiostations 玩摇滚如何删除该空间.还有我上面使用的其他技术.

http://www.mydomain.com/radioListGenre.php?genre=Radiostations playing Rock how can I remove this space. Is there any other technique the those I used above.

谢谢
潘卡(Pankaj)

Thanks
Pankaj

推荐答案

stringByAddingPercentEscapesUsingEncoding 和 stringByReplacingOccurrencesOfString 对提供的字符串进行操作，并返回字符串.您没有将返回值分配给任何内容，因此url不变，返回值只是消失在空间中.您想要更多类似的东西:

stringByAddingPercentEscapesUsingEncoding and stringByReplacingOccurrencesOfString operate on the string provided and return a string. You're not assigning the return value to anything so url isn't changing, the return value is just vanishing into space. You want something more like:

url = [url stringByAddingPercentEscapesUsingEncoding: NSASCIIStringEncoding];

假设url是可变的字符串.现在url包含url的修改版本.没有分配，它的作用与执行以下操作相同:

assuming url is a mutable string. Now url contains the modified version of url. Without the assignment it's effective the same as doing something like this:

a + 1;

代替:

a = a + 1

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