如何通过将文件名匹配文本文件中名称的子字符串来重命名文件 [英] How to rename file by matching filename to substring of name in textfile

问题描述

我有一个包含300个文件的目录，如下所示:

I have a directory with 300 files that look like this:

S221_L001_R2_001.fastq.gz   S30_L001_R2_001.fastq.gz    
S95_L001_R2_001.fastq.gz    S159_L001_R2_001.fastq.gz   
S222_L001_R2_001.fastq.gz   S31_L001_R2_001.fastq.gz    
S96_L001_R2_001.fastq.gz

我有一个文本文件，如下所示:

I have a text file that looks like this:

G1F0Blank3_S184_L001_R1_001.fastq.gz
G1F0Blank3_S184_L001_R2_001.fastq.gz
G1F0C1A_S101_L001_R1_001.fastq.gz
G1F0C1A_S101_L001_R2_001.fastq.gz
G1F0C1B_S154_L001_R1_001.fastq.gz
G1F0C1B_S154_L001_R2_001.fastq.gz

我想将文本文件中文件名前面的字符串添加到目录中的匹配文件中.在文本文件中，目录中的每个文件都有一个条目.我最希望能够在我的unix终端中执行此操作.

I would like to add the string in front of the filename in the text file to the matching file in my directory. There is one entry in the text file for each file in my directory. I would most like to be able to do this in my unix terminal.

谢谢！

推荐答案

for var in *                                                                                                                                                                        
do                                                                                                                                                                                                                                                                                                                                                         
newFileName=`grep -i $var /path/to/newNamefile`                                                                                                                                                 
if [ $? -eq 0 ]                                                                                                                                                                     
then                                                                                                                                                                                
mv $var $newFileName                                                                                                                                                                
fi                                                                                                                                                                                  
done

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