通过重新排列文件名来批量重命名目录中的文件 [英] Batch Rename Files in a Directory By Rearranging Filenames

问题描述

我在目录中有大量文件，其命名方式为:"[日期] [姓氏] 345.pdf".注意:所有345都是常数

I have a large number of files in a directory with this type of naming convention: "[Date] [Lastname] 345.pdf". Note: the 345 is constant for all of them

我想重命名所有文件，以便它们显示为"[姓氏] [日期] 345.pdf".

I would like to rename all of the files so that they read "[Lastname] [Date] 345.pdf".

我最初在这里输入错字

我在以下方面取得了一些成功:

I have had some success with:

gci -Filter *.pdf| %{Rename-Item $_.fullname $_.Name.Split(" ")[1]}

但是，这只给了我"[Date] .pdf".基本上，我不知道如何使用上述命令来组合拆分的两个不同部分.我基本上想要"[1] [0] [2] .pdf".

But that only gives me "[Date].pdf". Basically, I can't figure out how to use the above command to combine two different parts of the split. I basically want "[1] [0] [2].pdf" if that makes any sense.

谢谢.

推荐答案

使用正则表达式的另一种方法:

Another approach, using regular expressions:

Get-ChildItem *.pdf | % {
  $newName = $_.Name -replace '^(.*) (\S+) (\S+\.pdf)$', '$2 $1 $3'
  Rename-Item $_ $newName
}

正则表达式细分:

• ^(.*)匹配字符串开头的任意数量的字符，并将它们捕获到一个组中. [Date]在您的示例文件名[Date] [Lastname] 345.pdf中.
• (\S+)匹配一个或多个连续的非空白字符，并将它们捕获在第二组中. [Lastname]在您的示例文件名[Date] [Lastname] 345.pdf中.
• (\S+\.pdf)$匹配一个或多个连续的非空白字符，然后在字符串的末尾匹配字符串.pdf并将其捕获在第三组中. 345.pdf在您的示例文件名[Date] [Lastname] 345.pdf中.

• ^(.*) matches any number of characters at the beginning of the string and captures them in a group. [Date] in your example filename [Date] [Lastname] 345.pdf.
• (\S+) matches one or more consecutive non-whitespace characters and captures them in a second group. [Lastname] in your example filename [Date] [Lastname] 345.pdf.
• (\S+\.pdf)$ matches one or more consecutive non-whitespace characters followed by the string .pdf at the end of the string and captures that in a third group. 345.pdf in your example filename [Date] [Lastname] 345.pdf.

$1，$2和$3引用了这些组，因此替换字符串'$2 $1 $3'以所需的方式对这些组进行重新排序.

The groups are referred to by $1, $2 and $3, so the replacement string '$2 $1 $3' re-orders the groups the way you want.

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