二进制重新$ P $一个.NET小数的psentation [英] Binary representation of a .NET Decimal

问题描述

嘿，快速的问题：如何做一个.NET 十进制键入得到psented二进制在内存中再$ P $？

Hey all, quick question: How does a .NET decimal type get represented in binary in memory?

我们都知道浮点数存储和正是如此的原因，其不准确，但我无法找到十进制除以下的信息：

We all know how floating-point numbers are stored and the thusly the reasons for the inaccuracy thereof, but I can't find any information about decimal except the following:

1. 显然比浮点数更精确
2. 采用128位的内存
3. 2 ^ 96 +符号范围
4. 28（有时29？）的数量总显著位数

有什么办法，我可以想出解决办法？在我的计算机科学家需要的答案，并试图研究一个小时后，我找不到它。好像有任何浪费许多位或者我只是想象这个错误在我的脑海。任何人都可以提供一些线索对这个好吗？谢谢你。

Is there any way I can figure this out? The computer scientist in me demands the answer and after an hour of attempted research, I cannot find it. It seems like there's either a lot of wasted bits or I'm just picturing this wrong in my head. Can anyone shed some light on this please? Thanks.

推荐答案

<一个href="http://msdn.microsoft.com/en-us/library/system.decimal.getbits.aspx"><$c$c>Decimal.GetBits对于信息你想要的。

Decimal.GetBits for the information you want.

基本上它是一个96位整数的尾数，再加上一个符号位，再加上一个指数，以说有多少的十进制的地方将它转移到右侧。

Basically it's a 96 bit integer as the mantissa, plus a sign bit, plus an exponent to say how many decimal places to shift it to the right.

因此​​，要重新present 3.261你有3261尾数，0（即正）符号位，和3。需要注意的是十进制的指数是不归（故意），这样你就可以也的重新present 3.2610通过使用32610尾数和4的指数，例如

So to represent 3.261 you'd have a mantissa of 3261, a sign bit of 0 (i.e. positive), and an exponent of 3. Note that decimal isn't normalized (deliberately) so you can also represent 3.2610 by using a mantissa of 32610 and an exponent of 4, for example.

我在我的十进制浮点文章更多的信息。

I have some more information in my article on decimal floating point.

这篇关于二进制重新$ P $一个.NET小数的psentation的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！