无法通过beautifulsoup webscraping python获取标签"rel" [英] Cant get the tag 'rel' via beautifulsoup webscraping python

问题描述

我正在尝试在网站上测试beautifulsoup4 webscrape代码.已经完成了大多数操作，但是由于其位置的缘故，一个属性信息对我来说很难完成.

I am trying to test a beautifulsoup4 webscrape code on a website. Have done most of it but one attribute information due to its location is little tricky for me to accomplish.

代码如下:

span class="callseller-description-icon">
<a id="phone-lead" class="callseller-description-link" rel="0501365082" href="#">Show Phone Number</a>

我正在尝试此操作，但不确定是否可以

I am trying this but not sure if its okay

try:
        phone=soup.find('a',{'id':'phone-lead'})
        for a in phone:
            phone_result= str(a.get_text('rel').strip().encode("utf-8"))
        print "Phone information:", phone_result
    except StandardError as e:
        phone_result="Error was {0}".format(e)
        print phone_result

可能是我的错误.很难获得具有电话号码的 rel 信息

What is possibly my mistake. It kinda hard to get the rel information which has phone numbers

我得到的错误是

NavigableString object has no attribute get_text

推荐答案

find 返回元素而不是列表，如果要所有 a 标记，请使用

find returns the element not a list, if you want all a tags, use the find_all method. Also to get the rel attribute you need to use the .get() method or dictionary lookup. You can also add rel=True to get only those "a" tags where with the "rel" attribute.

演示:

• 使用 find()

>>> soup.find('a', {'id': 'phone-lead', 'rel': True}).get('rel')
['0501365082']

使用 find_all :

>>> for a in soup.find_all('a', {'id':'phone-lead', 'rel': True}):
...     print(a['rel'])
... 
['0501365082']

要获取所有相关"列表，您可以使用列表理解

To get a list of all "rel" you can use a list comprehensions

>>> [rel for rel in a['rel'] for a in soup.find_all('a', {'id':'phone-lead', 'rel': True})]
['0501365082']

这篇关于无法通过beautifulsoup webscraping python获取标签"rel"的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！