通过测试numpy数组中的每个元素是否在2个数字之间来创建布尔数组 [英] Creating a boolean array by testing if each element in numpy array is between 2 numbers

问题描述

我有一个数字的numpy数组，我想创建一个具有相同大小和尺寸的布尔数组，该数组说明该元素是否位于2个数字之间.例如:

I have a numpy array of numbers and i want to create a boolean array of the same size and dimensions that says whether or not that element lies between 2 numbers. For example:

a=np.array([[1,2,3],[4,5,6],[7,8,9]])

我知道我是否写信，

print a>3

我得到一个数组，该数组的前三个元素为"False"，其余的为"True"

I get an array that has the first three elements "False" and the rest "True"

np.array([[False,False,False],[True,True,True],[True,True,True]])

但是我想得到一个条件满足的布尔数组

But i want to get a boolean array where the conditions are such that

a>3 and a<8

有没有一种方法，而无需在for循环中逐个检查每个元素?我的数组是2048 * 2048，并且花费的时间太长了

Is there a way to do this without checking every element one by one in a for loop? I have arrays that are 2048*2048 and that takes too long

有人报告说，这与另一个解决方案使用numpy.where函数的问题相同，但是返回条件为true的元素，我的问题是返回布尔值

Some has reported that is is the same question as another where the solution was to use the numpy.where function, but that returns the elements where a condition is true, my question is to return booleans

推荐答案

您可以检查以下范围:

print (3<a)&(a<8)

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