Swift:使用给定示例拆分[String]导致[[String]]的正确方法是什么? [英] Swift : what is the right way to split up a [String] resulting in a [[String]] with a given example?

问题描述

从较大的[String]和给定的子数组大小开始，将这个数组拆分为较小的数组的最佳方法是什么?(最后一个数组将小于给定的子数组大小.)

Starting with a large [String] and a given subarray size, what is the best way I could go about splitting up this array into smaller arrays? (The last array will be smaller than the given subarray size).

具体示例:拆分[[1，" 2，" 3，" 4，" 5，" 6，" 7，" 8，" 9]，最大拆分大小为4

Concrete example: Split up ["1","2","3","4","5","6","7","8","9"] with max split size 4

代码将产生[["1"，"2"，"3"，"4"]，["4"，"5"，"6"，"7"]，["7"，"8，" 9]]

The code would produce [["1","2","3","4"],["4","5","6","7"],["7","8","9"]]

很显然，我可以手动进行一些操作，但是我觉得像map()或reduce()这样的东西可能会做得很漂亮.

Obviously I could do this a little more manually, but I feel like in swift something like map() or reduce() may do what I want really beautifully.

推荐答案

您可以对索引进行 map 到数组中:

You can map over the indices into you array:

extension Array {
    func chunked(size: Int) -> [[Element]] {
        let cnt = self.count
        return stride(from: 0, to: cnt, by: size).map {
            let end = Swift.min($0 + size, cnt)
            return Array(self[$0..<end])
        }
    }
}

["1","2","3","4","5","6","7","8","9"].chunked(size: 4)
// -> [["1", "2", "3", "4"], ["5", "6", "7", "8"], ["9"]]

["1","2","3","4","5","6","7","8","9"].chunked(size: 3)
// -> [["1", "2", "3"], ["4", "5", "6"], ["7", "8", "9"]]

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