将String与枚举值进行比较的正确方法是什么？ [英] What's the proper way to compare a String to an enum value?

问题描述

作业：Rock Paper Scissors游戏。

Homework: Rock Paper Scissors game.

我创建了一个枚举：

      enum Gesture{ROCK,PAPER,SCISSORS};

从中我想比较值来决定谁赢了 - 电脑或人。设置值工作正常，比较工作正常（纸覆盖岩石，岩石剪刀，剪刀剪纸）。但是，我不能让我的领带工作。用户在任何时候都会被公认为胜利者。

from which I want to compare values to decide who wins--computer or human. Setting the values works just fine, and the comparisons work properly (paper covers rock, rock crushes scissors, scissors cuts paper). However, I cannot get my tie to work. The user is declared as the winner any time there's a tie.

嗯...这个将会澄清： userPick 是一个 String ，值为 rock ， paper 或剪刀。我无法使用 == 将 userPick 与 computerPick ，正如你可以看到的，从我的枚举中转换为类型 Gesture 。

Ahhh...crap...this will clarify: userPick is a String with values rock, paper, or scissors. I'm unable to use == to compare userPick to computerPick, which, as you can see below, is cast as type Gesture from my enum.

      if(computer == 1)
         computerPick = Gesture.ROCK;
      else
         if(computer == 2)
           computerPick = Gesture.PAPER;
         else
           computerPick = Gesture.SCISSORS;
      if(userPick.equals(computerPick))
       {
          msg = "tie";
          ++tieGames;
       }
           etc....

我猜想有一个问题与 rock 不等于 ROCK 或 String userPick 无法匹配 Gesture computerPick ，因为后者不是 String 。但是，我无法在我的教科书或Oracle的Java教程中找到类似情况的例子，所以我不知道如何解决问题...

I am guessing that there's an issue with rock not being equal to ROCK, or the String userPick not being able to match Gesture computerPick because the latter isn't a String. However, I'm not able to find an example of a similar circumstance in my textbook or Oracle's Java Tutorials, so I'm not sure how to correct the problem...

任何提示？

推荐答案

我从您的问题收集 userPick 是一个 String 值。你可以这样比较：

I'm gathering from your question that userPick is a String value. You can compare it like this:

if (userPick.equalsIgnoreCase(computerPick.name())) . . .

除此之外，如果您确保计算机始终是 1 ， 2 或 3 （没有别的），您可以将它转换为手势枚举：

As an aside, if you are guaranteed that computer is always one of the values 1, 2, or 3 (and nothing else), you can convert it to a Gesture enum with:

Gesture computerPick = Gesture.values()[computer - 1];

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