从数组中删除重复的对象 [英] removing duplicate objects from an array

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本文介绍了从数组中删除重复的对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在致力于删除数组中的重复对象.我在尝试读取filterList [i + 1] .tagID时遇到错误.我可以手动输入[i + 1]值并获得正确的结果.我不确定为什么i + 1是个问题.我还想知道,使用slice [i,1]是否比删除更好?

I have been working on removing duplicate objects in an array. I keep getting an error on trying to read the filterList[i+1].tagID. I can manually enter the [i+1] values and get the correct results. I'm not sure why the i+1 is an issue. I have also wondered if if it better to use a slice[i, 1] than the delete.

const filterList = [{
  tagID: 1,
  tagName: "Red"
}, {
  tagID: 1,
  tagName: "Red"
}, {
  tagID: 2,
  tagName: "Orange"
}, {
  tagID: 2,
  tagName: "Orange"
}, {
  tagID: 5,
  tagName: "Blue"
}, {
  tagID: 5,
  tagName: "Blue"
}, {
  tagID: 5,
  tagName: "Blue"
}, {
  tagID: 6,
  tagName: "Indigo"
}, {
  tagID: 6,
  tagName: "Indigo"
}, {
  tagID: 7,
  tagName: "Violet"
}, {
  tagID: 7,
  tagName: "Violet"
}, {
  tagID: 7,
  tagName: "Violet"
}]

filterList.sort(function(a, b) {
  return a.tagID - b.tagID;
});

for (let i = 0; i < filterList.length; i++) {
  if (filterList[i].tagId == filterList[i+1].tagID) {
    delete filterList[i];
  }
}

console.log(filterList)

推荐答案

尝试一下!使用filter和es2015

Try this! Using filter and es2015

const filterListResult = filterList.filter((item, index, self) => index === self.findIndex((t) => (t.tagID === item.tagID && t.tagName === item.tagName)));
console.log(filterListResult);

<script>
const filterList = [{
  tagID: 1,
  tagName: "Red"
}, {
  tagID: 1,
  tagName: "Red"
}, {
  tagID: 2,
  tagName: "Orange"
}, {
  tagID: 2,
  tagName: "Orange"
}, {
  tagID: 5,
  tagName: "Blue"
}, {
  tagID: 5,
  tagName: "Blue"
}, {
  tagID: 5,
  tagName: "Blue"
}, {
  tagID: 6,
  tagName: "Indigo"
}, {
  tagID: 6,
  tagName: "Indigo"
}, {
  tagID: 7,
  tagName: "Violet"
}, {
  tagID: 7,
  tagName: "Violet"
}, {
  tagID: 7,
  tagName: "Violet"
}]
</script>

这篇关于从数组中删除重复的对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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