如何从JavaScript中的数组中删除重复的对象? [英] How to remove duplicates objects from array in javascript?

问题描述

在我的代码中，我创建了一个名为array1的数组.在这个数组中，我列出了多个对象.我想过滤掉array1对象的值作为唯一值，并且需要将ID与它们各自的值组合在一起.我在这里添加了代码，

In my code i have created one array called array1. In this array i have listed multiple objects. I want to filter out array1 objects values as unique and need to group ids with their respective values. I have added my code here,

Array1

var array1 = [
            {
                value:"A",
                id:1
            },
            {
                value:"B",
                id:1
            },
            {
                value:"C",
                id:2
            },
            {
                value:"B",
                id:5
            },
            {
                value:"A",
                id:2
            },
            {
                value:"A",
                id:1
            }
        ];

我想要的结果，

[
            {
                group:"A",
                groupIds:[1, 2]
            },
            {
                group:"B",
                groupIds:[1, 5]
            },
            {
                group:"C",
                groupIds:[2]
            }
        ]

推荐答案

您可以使用 forEach()将对象按值分组，并使用 Set()删除重复的ID来自 groupIds

You can use forEach() to group objects by values and Set() to remove duplicate ids from groupIds

var array1 = [{"value":"A","id":1},{"value":"B","id":1},{"value":"C","id":2},{"value":"B","id":5},{"value":"A","id":2},{"value":"A","id":1}]

var result = [];
array1.forEach(function(e) {
  if(!this[e.value]) (this[e.value] = {group: e.value, groupIds: []}) && result.push(this[e.value])
  this[e.value].groupIds = [...new Set(this[e.value].groupIds.concat(e.id))]
}, {})

console.log(result)

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