将uint8array转换为javascript中的double [英] Convert uint8array to double in javascript

问题描述

我有一个数组缓冲区，我想获取双精度值.例如，从[64，-124，12，0，0，0，0，0]中，我会得到641.5

I have an arraybuffer and I want to get double values.For example from [64, -124, 12, 0, 0, 0, 0, 0] I would get 641.5

有什么想法吗?

推荐答案

您可以采用 answer 中出色的 TJCrowder 并使用 给定字节的DataView#setUint8 .

You could adapt the excellent answer of T.J. Crowder and use DataView#setUint8 for the given bytes.

var data =  [64, -124, 12, 0, 0, 0, 0, 0];

// Create a buffer
var buf = new ArrayBuffer(8);
// Create a data view of it
var view = new DataView(buf);

// set bytes
data.forEach(function (b, i) {
    view.setUint8(i, b);
});

// Read the bits as a float/native 64-bit double
var num = view.getFloat64(0);
// Done
console.log(num);

对于多个数字，您可以取8的块.

For multiple numbers, you could take chunks of 8.

function getFloat(array) {
    var view = new DataView(new ArrayBuffer(8));
    array.forEach(function (b, i) {
        view.setUint8(i, b);
    });
    return view.getFloat64(0);
}

var data =  [64, -124, 12, 0, 0, 0, 0, 0, 64, -124, 12, 0, 0, 0, 0, 0],
    i = 0,
    result = [];

while (i < data.length) {
    result.push(getFloat(data.slice(i, i + 8)));
    i += 8;
}

console.log(result);

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