如何将十六进制字符串转换为Uint8Array并返回JavaScript? [英] How to convert a hexadecimal string to Uint8Array and back in JavaScript?
本文介绍了如何将十六进制字符串转换为Uint8Array并返回JavaScript?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想将 bada55
之类的十六进制字符串转换为 Uint8Array
,然后再返回。
I want to convert a hexadecimal string like bada55
into a Uint8Array
and back again.
推荐答案
Vanilla JS:
Vanilla JS:
const fromHexString = hexString =>
new Uint8Array(hexString.match(/.{1,2}/g).map(byte => parseInt(byte, 16)));
const toHexString = bytes =>
bytes.reduce((str, byte) => str + byte.toString(16).padStart(2, '0'), '');
console.log(toHexString(new Uint8Array([0, 1, 2, 42, 100, 101, 102, 255])))
console.log(fromHexString('0001022a646566ff'))
注意:此方法始终完成。如果十六进制编码缓冲区的长度不能被2整除,那么将解析最后一个字节,好像它前面加上 0
(例如 aaa
被解释为 aa0a
)。
Note: this method always completes. If the length of the hex-encoded buffer is not divisible by 2, the final byte will be parsed as if it were prepended with a 0
(e.g. aaa
is interpreted as aa0a
).
如果十六进制可能格式错误(例如用户输入),在调用此方法之前检查其长度并处理错误,例如:
If the hex is potentially malformed (e.g. user input), check its length and handle the error before calling this method, e.g.:
const missingLetter = 'abc';
if(missingLetter.length % 2 === 0){
throw new Error(`The string "${missingLetter}" is not divisible by 2.`)
}
fromHexString(missingLetter);
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