在iOS中从阵列获取重复项和原始项 [英] To Get Duplicate as well as original items from an array in iOS

问题描述

我有一个数组，例如

(约翰，简，约翰)

我想得到重复的像数组一样的原始元素

I want to get duplicates,as well as original elements of array like

(约翰，约翰)我可以从代码中得到一次出现此处

(John,John) I am able to get single occurance from code here

NSArray *names = [NSArray arrayWithObjects:@"John", @"Jane", @"John", nil];
NSCountedSet *set = [[NSCountedSet alloc] initWithArray:names];

for (id item in set)
{
    NSLog(@"Name=%@, Count=%lu", item, (unsigned long)[set countForObject:item]);
    if((unsigned long)[set countForObject:item]>1){
        NSLog(@"of repeated element-----=%@",item);
    }
} 

重复元素的名称----- John"，但我希望出现所有重复元素，例如重复元素的名称----- John，John".

"Name of repeated element-----John" but i want all occurences of repeated element like "Name of repeated element-----John,John" .

推荐答案

尝试此使用NSPredicate :

NSArray *array = [NSArray arrayWithObjects:@"John", @"Jane", @"John",@"Jane",@"Jane", nil];
NSMutableArray *arrResult = [[NSMutableArray alloc] init];
NSCountedSet *set = [[NSCountedSet alloc] initWithArray:array];
for(id name in set)
   {
        if([set countForObject:name] > 1 ){
            NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF = %@", name];
            [arrResult addObjectsFromArray:[array filteredArrayUsingPredicate:predicate]];
        }
    }
    //
    NSLog(@"%@",arrResult);

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