寻找一种构造多维多层关联数组的方法 [英] Searching for a way to construct a multidimensional, multilayered, associative Array

问题描述

因此，在遍历字符串并将其chars作为索引数组插入多维关联数组时遇到麻烦.所以基本上是一维多维数组中的一维多维数组.这有点麻烦，因为我无法手动完成.我需要一种自动化的方法来处理一堆字符串.下面的示例将对它进行一些解释，我认为:

So i am running into trouble while iterating through a string and inserting it's chars as index-arrays into a multidimensional,associative array. So basically a bunch of multidimensional arrays in multidimensional arrays in multidimensional arrays..... That is a bit troublesome as i cant do it by hand. I need an automated way to do this with a bunch of strings. The following example will explain it a bit better i think:

//string i want to enter
$string = 'ADAM';
//array i want to end up with
$result = array
              (
                'A'=> array
                 (
                  'D'=>array
                   (
                    'A'=>array
                     (
                      'M'=>array
                        (
                          'result'=>'ADAM'
                        )
                     )
                   )
                 )
               )

我最初的方法是使用if-conditions将第一个Char作为数组插入到主数组中，例如:

my initial approach was just using if-conditions to insert the first Char as Array into the main-array like:

for($i = 0; $i < strlen($string); $i++){
      if($i == 0){
       $array1[$word[$i]] = array();
      }
}

效果很好.但是后来我遇到了问题:如何跟踪数组中的当前点?在执行if-check之后，我将寻求一个else语句，该语句在$ i大于0时起作用.但是，如果我想插入数组的下一个维，在这种情况下为'D'，则我需要选择$ array1 ['A']，接下来，我将需要$ array1 ['A'] ['D']等.我无法找到一种方法.我需要进入此数组的字符串范围为4-70个字符.我所知道的每种方法都只改变了第二维，所以我最终得到了:

which works pretty well. But then i ran into my Problem: how do i keep track of the current point in the array? Following the if-check i would go for an else-statement that acts when $i is bigger than 0. But if i want to insert the next dimension of array, which would be 'D' in this case, i would need to select $array1['A'], for the next i would need $array1['A']['D'] etc. I wasn't able to find a way yet to do that. The strings i need to get into this array vary from 4-70 chars. Each method i know of only changed the 2nd dimension so i ended up with:

$array1('A'=>array ('A' =>array()));
$array1('A'=>array ('D' =>array()));
$array1('A'=>array ('A' =>array()));
$array1('A'=>array ('M' =>array()));

或由索引本身是数组引起的非法偏移错误.也许我在这里的方法是不可能的，但是我仍然认为我可能会问，以防我错过了一些东西.

or illegal offset-errors caused by the indexes being arrays themselves. Maybe my approach here is not possible, but i still thought i might ask in case i missed something.

在稍后阶段，im希望对所有字符串使用相同的数组，因此我基本上将Chars用作节点..如果已经存在作为第一个char的'A'，那么我将跳过它并插入下一个字符串的第二个char放入"A"数组等.

In a Later stage im looking to use the same array for all strings so i basically use the Chars as nodes.. if 'A' as first char already exists i would then skip that and insert the 2nd char of the next string into the 'A'-Array etc.

预先感谢！

推荐答案

您可以为此使用递归函数.

You can use a recursive function for this.

function nest(string $str, int $i = 0) {
    return isset($str[$i]) ? [$str[$i] => nest($str, $i + 1)] : ['result' => $str];
}

$result = nest($string);

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