如何使用Regex.Split分割字符串并保留所有分隔符? [英] How to split string with Regex.Split and keep all separators?

问题描述

如何使用Regex.Split分割字符串并保留所有分隔符?

How to split string with Regex.Split and keep all separators?

我有一个字符串:"substring1 delimeter1 substring2"，其中delimeter + substring2是地址的一部分.

I have a string:"substring1 delimeter1 substring2" , where delimeter+substring2 is a part of address.

我也有2个或更多的分度符:delim1，delim2的含义是相等的；

Also i have 2 and more delimeters: delim1,delim2 wich are equivalent in meaning;

我想得到这样的字符串数组:

And i want to get string array like this:

arr[0]="subsctring1";
arr[1]="delim1 subsctring2";

或

arr[1]="delim2 subsctring2;

我有一个模式:

addrArr= Regex.Split(inputText, String.Concat("(?<=",delimeter1, "|",delimeter2, ")"), RegexOptions.None);

但是效果不佳.

您能帮我建立一个有效的模式吗?

Can you help me to create a valid pattern to to that?

推荐答案

您只需要具有前瞻性的模式:

You need a pattern with a lookahead only:

\s+(?=delim1|delim2)

\ s + 将匹配1个或多个空格(因为您的字符串包含空格).如果没有空格，请使用 \ s * (但是您将需要从结果中删除空条目).请参见

The \s+ will match 1 or more whitespaces (since your string contains whitespaces). In case there can be no whitespaces, use \s* (but then you will need to remove empty entries from the result). See the regex demo. If these delimiters must be whole words, use \b word boundaries: \s+(?=\b(?:delim1|delim2)\b).

在C#中:

addrArr = Regex.Split(inputText, string.Format(@"\s+(?={0})", string.Join("|", delimeters)));

如果定界符可以包含特殊的正则表达式元字符，则需要在定界符列表上运行 Regex.Escape .

If the delimiters can contain special regex metacharacters, you will need to run Regex.Escape on your delimiters list.

C#演示:

var inputText = "substring1 delim1 substring2 delim2 substr3";
var  delimeters = new List<string> { "delim1", "delim2" };
var addrArr = Regex.Split(inputText, 
        string.Format(@"\s+(?={0})", string.Join("|", delimeters.Select(Regex.Escape))));
Console.WriteLine(string.Join("\n", addrArr));

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