如何等待所有任务完成而不会阻塞UI线程? [英] How to wait until all tasks finished without blocking UI thread?
本文介绍了如何等待所有任务完成而不会阻塞UI线程?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在下面的代码中,我在处理任务之前禁用了按钮,并希望在所有任务完成后启用它.
In the following code I disable button before processing tasks and would like to enable it after all tasks are finished.
List<Task> tasks = new List<Task>();
buttonUpdateImage.Enabled = false; // disable button
foreach (OLVListItem item in cellsListView.CheckedItems)
{
Cell c = (Cell)(item.RowObject);
var task = Task.Factory.StartNew(() =>
{
Process p = new Process();
...
p.Start();
p.WaitForExit();
});
task.ContinueWith(t => c.Status = 0);
tasks.Add(task);
}
Task.WaitAll(tasks.ToArray());
// enable button here
WaitAll
阻止了UI线程.如何等待所有任务完成然后启用按钮?
WaitAll
is blocking the UI thread. How can I wait until all tasks finish and then enable the button?
推荐答案
首先,我将安装现在,使用这个问题的答案,您可以异步注册进程退出,而无需使用 Task.Factory.StartNew
:
Now, using the answer to this question, you can asynchronously register for process exit, with no need to use Task.Factory.StartNew
:
public static class ProcessExtensions
{
public static Task RunProcessAsync(this Process process, string fileName)
{
if (process == null)
throw new ArgumentNullException(nameof(process));
var tcs = new TaskCompletionSource<bool>();
process.StartInfo = new ProcessStartInfo
{
FileName = fileName
};
process.EnableRaisingEvents = true
process.Exited += (sender, args) =>
{
tcs.SetResult(true);
process.Dispose();
};
process.Start();
return tcs.Task;
}
}
现在,您可以执行以下操作:
Now, you can do this:
buttonUpdateImage.Enabled = false; // disable button
var tasks = cellsListView.CheckedItems.Cast<OLVListItem>()
.Select(async item =>
{
Cell cell = (Cell)item.RowObject;
var process = new Process();
await process.RunProcessAsync("path");
cell.Status = 0;
});
await Task.WhenAll(tasks);
buttonUpdateImage.Enabled = true;
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