仅在大括号外的空格上分割字符串 [英] split a string only on spaces that are outside curly braces

问题描述

我是regex的新手，我需要一些帮助.我阅读了一些与此问题相似的主题，但是我不知道该如何解决.

I am new to regex and I need some help. I read some topics similar to this issue, but I could not figure out how to resolve it.

我需要在不在一对大括号内的每个空白处分割一个字符串.大括号外的连续空格应视为一个空格:

I need to split a string on every blank space that is not inside a pair of curly braces. Consecutive blank spaces outside the curly braces shall be considered as a single one:

{ TEST test } test { test test} {test test  }   { 123 } test  test 

结果:

{ TEST test } 

test 

{ test test} 

{test test  }   

{ 123 } 

test  

test

推荐答案

\{[^}]+\}|\S+

这将匹配用花括号括起来的所有字符或非空格字符.从字符串中获取所有与之匹配的内容应该会为您提供所需的内容.

This matches either a run of any characters enclosed by curly braces, or a run of non-space characters. Grabbing all of the matches for it out of your string should provide you with what you want.

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